题目内容
已知数列
中,
.
(1)设
,求证:数列
是常数列,并写出其通项公式;
(2)设
,求证:数列
是等比数列,并写出其通项公式;
(3)求数列
的通项公式.


(1)设
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
(2)设


(3)求数列

(1)
(2)
(3)



(1)利用常数列的定义即证:bn+1=bn即可.
(2)利用等比数列的定义证明:
再进一步证明出其比值是一个与n无关的常数即可.
(3)在(2)的基础上,可由
,通过叠加的方法求an即可
(1)证明:∵
∴
又∵
∴
∴
是常数列,且
……………(3分)
……(4分)
(2)证明∵
∴
又∵
∴
而
∴
是以2为首项,2为公比的等比数列………………(7分)
∴
…………(8分)
(3)解:
①
②
②-①得
(2)利用等比数列的定义证明:

(3)在(2)的基础上,可由

(1)证明:∵

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
∴

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
(2)证明∵


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∴

(3)解:


②-①得


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