题目内容
如图,平行六面体
中,侧棱
长为3,底面是边长为2的菱形,![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438286730.png)
点E在棱
上,则
的最小值为( )
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240104383493233.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438255787.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438271382.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438286730.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438302730.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438271382.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438317601.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240104383493233.png)
A.![]() | B.5 | C.![]() | D.7 |
A
试题分析:
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240104383804613.png)
解:将面C1CB1B,B1BAA1打开,如图,由已知得C,B,A共线,连接AC1,则AC1为AE+C1E的最小值,
平行六面体中,侧棱B1B长为3,底面是边长为1的菱形,∠A1AB=120°,∠A1AD=60°,点E在棱B1B上,
∴CA=1+1=2,C1C=3,∴cos∠C1CA=cos60°=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438395338.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438349341.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824010438349341.png)
点评:本题考查线段和最小值的求法,解题时要认真审题,仔细解答,注意等价转化思想的合理运用
![](http://thumb.zyjl.cn/images/loading.gif)
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