题目内容
在直角坐标系中,以原点为极点,x轴的正半轴为极轴建立极坐标系,已知曲线C:
(
>0),已知过点P(-2,-4)的直线l的参数方程为:
(t为参数),直线l与曲线C分别交于M,N两点.
(1)写出曲线C和直线l的普通方程;
(2)若|PM|,|MN|,|PN|成等比数列,求
的值.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906650815.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906665278.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240529066811245.png)
(1)写出曲线C和直线l的普通方程;
(2)若|PM|,|MN|,|PN|成等比数列,求
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906665278.png)
(1) 曲线C:
, 直线
的普通方程为
;(2)
.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906712593.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906728280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906759503.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906774336.png)
试题分析:(1) 由
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240529067901228.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906650815.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906821678.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906837716.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906852267.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240529069151042.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906930508.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906665278.png)
解:(1)由
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906650815.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906712593.png)
直线l的普通方程为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906759503.png)
(2)直线l的参数方程为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240529070081245.png)
代入
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906712593.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240529069151042.png)
设两交点M,N对应的参数分别为t1,t2,
则有
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052907055859.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052907071764.png)
因为|MN|2=|PM|·|PN|,所以(t1-t2)2=(t1+t2)2-4t1·t2=t1·t2,
解得
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824052906774336.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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