题目内容
如右图所示,已知正方形和矩形所在的平面互相垂直,,AF = 1,M是线段的中点.
(1)求证:平面;
(2)求证:平面;
(3)求二面角的大小.
(1)求证:平面;
(2)求证:平面;
(3)求二面角的大小.
(1) 设,连结EO
∵ O、M分别是AC、EF的中点,
四边形ACEF为矩形························ 2分
∴ AM∥EO
∵ EO面BDE,AM面BDE
∴ AM∥面BDE·························· 4分
(2) 由已知有BD⊥面ACEF
∴ BD⊥AM···························· 5分
又,知四边形AOMF为正方形
∴ FO⊥AM···························· 6分
又
∴ AM⊥面BDF·························· 8分
(3) 令,作HG⊥DF于G,连结AG,由三垂线定理知AG⊥DF
∴ ∠AGH为所求的二面角的平面角················· 10分
易算得···················· 12分
∴
∴ 所求二面角的大小为60··················· 13分
∵ O、M分别是AC、EF的中点,
四边形ACEF为矩形························ 2分
∴ AM∥EO
∵ EO面BDE,AM面BDE
∴ AM∥面BDE·························· 4分
(2) 由已知有BD⊥面ACEF
∴ BD⊥AM···························· 5分
又,知四边形AOMF为正方形
∴ FO⊥AM···························· 6分
又
∴ AM⊥面BDF·························· 8分
(3) 令,作HG⊥DF于G,连结AG,由三垂线定理知AG⊥DF
∴ ∠AGH为所求的二面角的平面角················· 10分
易算得···················· 12分
∴
∴ 所求二面角的大小为60··················· 13分
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