ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ËÄÖÖ¶ÌÖÜÆÚÖ÷×åÔªËØX¡¢Y¡¢Z¡¢WµÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó¡£»¯ºÏÎï¼×ÓÉX¡¢Y¡¢ZÈýÖÖÔªËØ×é³É£¬25¡æʱ£¬0.01mol/L ¼×ÈÜÒºÖеÄc(OH-)/c(H+)=1010£»ZÓëW ͬÖÜÆÚ£¬ÇÒWµÄ×î¸ß»¯ºÏ¼ÛÓë×îµÍ»¯ºÏ¼ÛµÄ´úÊýºÍΪ4¡£ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ
A. µÈÎïÖʵÄÁ¿µÄ»¯ºÏÎïZ2Y2 ÓëZ2WµÄÒõÀë×Ó¸öÊýÏàͬ
B. Ô×Ӱ뾶X
C. Õ´ÓÐWµÄµ¥ÖʵÄÊԹܿÉÓþƾ«Ï´µÓ
D. ¼òµ¥Ç⻯ÎïµÄÎȶ¨ÐÔY
¡¾´ð°¸¡¿A
¡¾½âÎö¡¿ËÄÖÖ¶ÌÖÜÆÚÖ÷×åÔªËØX¡¢Y¡¢Z¡¢WµÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬»¯ºÏÎï¼×ÓÉX¡¢Y¡¢ZÈýÖÖÔªËØ×é³É£¬25¡æʱ£¬0.01molL-1¼×ÈÜÒºÖÐ=1010£¬¿ÉÖªc(OH-)=0.01mol/L£¬Ôò¼×ΪNaOH£¬½áºÏÔ×ÓÐòÊý¿ÉÖªXΪH£¬YΪO£¬ZΪNa£¬ZÓëWͬÖÜÆÚ£¬ÇÒWµÄ×î¸ßÕý¼ÛÓë×îµÍ¸º¼ÛµÄ´úÊýºÍΪ4£¬Æä×î¸ß¼ÛΪ+6¼Û£¬¿ÉÖªWΪS¡£ÓÉÉÏÊö·ÖÎö¿ÉÖª£¬XΪH£¬YΪO£¬ZΪNa£¬WΪS¡£A. ¹ýÑõ»¯ÄƺÍÁò»¯ÄÆÖеÄÒõÀë×Ó·Ö±ðΪ¹ýÑõ¸ùÀë×ÓºÍÁòÀë×Ó£¬µÈÎïÖʵÄÁ¿µÄ»¯ºÏÎï¹ýÑõ»¯ÄƺÍÁò»¯ÄƵÄÒõÀë×Ó¸öÊýÏàͬ£¬¹ÊAÕýÈ·£»B£®µç×Ó²ãÔ½¶à£¬Ô×Ӱ뾶Խ´ó£¬Í¬ÖÜÆÚ´Ó´Ó×óÏòÓÒÔ×Ӱ뾶¼õС£¬ÔòÔ×Ӱ뾶£ºX£¼Y£¼W£¼Z£¬¹ÊB´íÎó£»C£®S΢ÈÜÓھƾ«£¬Ò×ÈÜÓÚCS2£¬Ó¦Ñ¡CS2Ï´µÓ£¬¹ÊC´íÎó£»D£®·Ç½ðÊôÐÔԽǿ£¬¶ÔÓ¦Ç⻯ÎïÔ½Îȶ¨£¬¼òµ¥Ç⻯ÎïµÄÎȶ¨ÐÔ£ºY£¾W£¬¹ÊD´íÎó£»¹ÊÑ¡A¡£
¡¾ÌâÄ¿¡¿2017Ä꣬ÖпÆÔº´óÁ¬»¯Ñ§ÎïÀíÑо¿Ëù̼×ÊԴС·Ö×ÓÓëÇâÄÜÀûÓô´ÐÂÌØÇøÑо¿×飨DNL19T3£©Ëï½£¡¢¸ðÇì½ÜÑо¿Ô±ÍŶÓͨ¹ýÉè¼ÆÒ»ÖÖÐÂÐÍNa-Fe3O4/HZSM-5¶à¹¦Äܸ´ºÏ´ß»¯¼Á£¬³É¹¦ÊµÏÖÁËCO2Ö±½Ó¼ÓÇâÖÆÈ¡¸ßÐÁÍéÖµÆûÓÍ¡£¸ÃÑо¿³É¹û±»ÆÀ¼ÛΪ¡°CO2´ß»¯×ª»¯ÁìÓòµÄÍ»ÆÆÐÔ½øÕ¹¡±¡£
(1) ¹¤ÒµÉú²úβÆøÖеÄCO2²¶»ñ¼¼ÊõÖ®Ò»ÊÇ°±Ë®ÈÜÒºÎüÊÕ¼¼Êõ£¬¹¤ÒÕÁ÷³ÌÊǽ«ÑÌÆøÀäÈ´ÖÁ15.5¡«26.5¡æºóÓð±Ë®ÎüÊÕ¹ýÁ¿µÄCO2£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________¡£ÔÚÓð±Ë®ÎüÊÕÇ°£¬ÑÌÆøÐèÀäÈ´ÖÁ15.5¡«26.5¡æµÄ¿ÉÄÜÔÒòÊÇ_________________¡£
(2) ¸ÃÑо¿³É¹ûÓÃCO2ÖÆÈ¡¸ßÐÁÍéÖµÆûÓ͵Ä·ÏßÊÇÏȽ«CO2°´ÄæˮúÆø·´Ó¦Éú³ÉCO£¬È»ºóÓÉCOÓëH2·´Ó¦Éú³ÉÌþ£¬²úÎïÖÐÆûÓÍ×é·ÖÕ¼ËùÓÐÌþÀà²úÎïµÄ°Ù·Ö±È½ü80%¡£
¢Ù ÒÑÖª£ºH2 (g)£«O2 (g) === H2O(l) ¦¤H1= ¡ª285.8 kJ¡¤mol-1
C8H18(l)£«O2(g) === 8CO2(g)£«9H2O(l) ¦¤H3= ¡ª5518 kJ¡¤mol-1
ÊÔд³ö25¡æ¡¢101kPaÌõ¼þÏ£¬CO2ÓëH2·´Ó¦Éú³ÉÆûÓÍ(ÒÔC8H18±íʾ)µÄÈÈ»¯Ñ§·½
³Ìʽ__________________________¡£
¢Ú ÔÚһʵÑéÈÝÆ÷ÖгäÈëÒ»¶¨Á¿µÄCO2ºÍH2£¬Èô¼ÓÈë´ß»¯¼ÁÇ¡ºÃÍêÈ«·´Ó¦£¬ÇÒ²úÎïÖ»Éú³ÉC5ÒÔÉϵÄÌþÀàÎïÖʺÍË®£¬ÔòCO2ÓëH2µÄÎïÖʵÄÁ¿Ö®±È²»µÍÓÚ________¡£
(3) ¶þ¼×ÃÑ(CH3OCH3)µÄÊ®ÁùÍéÖµ¸ß£¬È¼ÉÕβÆøÖÐÎÛȾÎïÉÙ£¬¿É´úÌæ²ñÓÍ¡£CO¡¢CO2»ìºÏ¼ÓÇâµÄ·½·¨ÊÇÔÚÒ»¸ö·´Ó¦Æ÷Öн«ºÏ³ÉÆøÖ±½Óת»¯Îª¶þ¼×ÃÑ£¬°üÀ¨ÒÔÏÂ4¸ö·´Ó¦£º
CO2(g)£«3H2(g)CH3OH(g)£«H2O(g) ¢Ù
CO2(g)£«H2(g)CO(g)£«H2O(g) ¡¡ ¢Ú
CO(g)£«2H2(g)CH3OH(g) ¢Û
2CH3OH(g)CH3OCH3(g)£«H2O(g) ¢Ü
¢Ù ÒÑÖª·´Ó¦¢ÜÔÚijζÈϵÄƽºâ³£ÊýΪK=400¡£´ËζÈÏ£¬ÔÚÒ»ºãÈÝÃܱÕÈÝÆ÷ÖмÓÈëCH3OH£¬·´Ó¦µ½Ä³Ê±¿Ì²âµÃ¸÷×é·ÖµÄŨ¶ÈÈçÏ£º
ÎïÖÊ | CH3OH | CH3OCH3 | H2O |
Ũ¶È/£¨mol¡¤L£1£© | 0.44 | 0.6 | 0.6 |
´ËʱÕý¡¢Äæ·´Ó¦ËÙÂʵĴóС£ºv(Õý) ______ v(Äæ) £¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°£½¡±)¡£
Èô¼ÓÈëCH3OHºó£¬¾10 min·´Ó¦´ïµ½Æ½ºâ£¬¸Ãʱ¼äÄÚ·´Ó¦ËÙÂÊv(CH3OH)£½_____¡£
¢Ú ij¿ÆÑÐС×éÔÚ·´Ó¦Î¶È503K¡«543K£¬·´Ó¦Ñ¹Ç¿·Ö±ðÊÇ3¡¢4¡¢5¡¢6¡¢7MPa£¬n(CO)/n(CO+CO2)=0.5µÄÇé¿öϼÆËãÁ˶þ¼×ÃѵÄƽºâÊÕÂÊ(¶þ¼×ÃÑʵ¼Ê²úÁ¿Óë·´Ó¦Îï×ÜÁ¿Ö®±È)£¬½á¹ûÈçͼ1Ëùʾ¡£
a~eÇúÏß·Ö±ð¶ÔÓ¦²»Í¬µÄѹǿÌõ¼þ£¬Ôòe¶ÔÓ¦µÄѹǿÊÇ______£¬ÀíÓÉÊÇ___________¡£
¸Ã¿ÆÑÐС×éÔÚ·´Ó¦Î¶È523K¡¢·´Ó¦Ñ¹Ç¿5MPaµÄÌõ¼þÏ£¬°´Õպϳɷ´Ó¦µÄ»¯Ñ§¼ÆÁ¿±È½øÁÏ£¬¸Ä±än(CO)/n(CO+CO2)µÄ±ÈÀý£¬¶þ¼×ÃѵÄƽºâÊÕÂʵı仯¹æÂÉÈçͼ2Ëùʾ¡£
ÓÉͼ2¿ÉÖª£¬¶þ¼×ÃѵÄƽºâÊÕÂÊËæ×Ån(CO)/n(O+CO2)±ÈÖµµÄÔö´ó¶øµ¥µ÷ÉÏÉý£¬ÆäÔÒòÊÇ________________________________________________¡£