ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÒÑÖª X¡¢Y¡¢Z¡¢Q¡¢R¡¢EÁùÖÖÇ°ËÄÖÜÆÚÔªËØÖУ¬Ô­×ÓÐòÊýX£¼Y£¼Z£¼Q£¼R£¼E£¬Æä½á¹¹»òÐÔÖÊÐÅÏ¢ÈçÏÂ±í¡£

ÔªËØ

½á¹¹»òÐÔÖÊÐÅÏ¢

X

Ô­×ÓµÄL²ãÉÏsµç×ÓÊýµÈÓÚpµç×ÓÊý

Y

Ô­×ÓºËÍâµÄL²ãÓÐ3¸öδ³É¶Ôµç×Ó

Z

µØ¿ÇÖк¬Á¿×î¶àµÄÔªËØ

Q

µ¥Öʳ£Î³£Ñ¹ÏÂÊÇÆøÌ壬ԭ×ÓµÄM²ãÉÏÓÐ1¸öδ³É¶ÔµÄpµç×Ó

R

ºËµçºÉÊýÊÇYÓëQµÄºËµçºÉÊýÖ®ºÍ

E

NÄܲãÉÏÖ»ÓÐÒ»¸öµç×Ó£¬K¡¢L¡¢M²ã¾ùÅÅÂúµç×Ó

£¨1£©Ð´³öÔªËØYµÄÔ­×ÓºËÍâ¼Ûµç×ÓÅŲ¼Í¼£º________________¡£XµÄÒ»ÖÖÇ⻯ÎïÏà¶Ô·Ö×ÓÖÊÁ¿Îª26£¬Æä·Ö×ÓÖеĦҼüÓë¦Ð¼üµÄ¼üÊýÖ®±ÈΪ__________¡£

£¨2£©X¡¢Y¡¢ZÈýÖÖÔªËصĵÚÒ»µçÀëÄÜÓɸߵ½µÍµÄÅÅÁÐΪ£¨Ð´ÔªËØ·ûºÅ£©__________¡£ÈýÖÖÔªËص縺ÐÔÓÉ´óµ½Ð¡µÄ˳ÐòΪ£¨ÌîÔªËØ·ûºÅ£©_____________¡£

£¨3£©X¡¢ZÔªËØ·Ö±ðÓëÇâÔªËØÐγɵÄ×î¼òµ¥»¯ºÏÎïÖУ¬·Ðµã½Ï¸ßµÄΪ£¨Ð´»¯Ñ§Ê½£©__________£¬Ô­ÒòÊÇ________________¡£

£¨4£©XZÓëY2ÊôÓڵȵç×ÓÌ壬д³ö»¯ºÏÎïXZµÄ½á¹¹Ê½£º________________¡£

£¨5£©RµÄÒ»ÖÖÅäºÏÎïµÄ»¯Ñ§Ê½ÎªRCl3¡¤6H2O¡£ÒÑÖª0.01 mol RCl3¡¤6H2OÔÚË®ÈÜÒºÖÐÓùýÁ¿ÏõËáÒøÈÜÒº´¦Àí£¬²úÉú0.02 mol AgCl³Áµí¡£´ËÅäºÏÎï×î¿ÉÄÜÊÇ________________¡£

A£®[R(H2O)6]Cl3 B£®[R(H2O)5Cl]Cl2¡¤H2O

C£®[R(H2O)4Cl2]Cl¡¤2H2O D£®[R(H2O)3Cl3]¡¤3H2O

¡¾´ð°¸¡¿ 3¡Ã2 N>O>C O > N >C H2O Ë®·Ö×Ó¼ä¿ÉÒÔÐγÉÇâ¼ü£¬Ê¹·ÐµãÉý¸ß C¡ÔO B

¡¾½âÎö¡¿ÊÔÌâ·ÖÎö£º±¾Ìâͨ¹ý¶ÔÁùÖÖÔªËصÄÍƶϣ¬Ö÷Òª¿¼²éÔ­×ÓºËÍâµç×ÓÅŲ¼¡¢¼Ûµç×ÓÅŲ¼Í¼¡¢¦Ò¼üÓë¦Ð¼ü¡¢µç¸ºÐÔ¡¢µÚÒ»µçÀëÄÜ¡¢Çâ¼ü¼°Æä¶ÔÎïÖÊÎïÀíÐÔÖʵÄÓ°Ïì¡¢µÈµç×ÓÌå¡¢ÅäºÏÎï½á¹¹µÈ֪ʶ£¬Öص㿼²é¿¼ÉúÔªËصÄ×ÛºÏÍƶÏÄÜÁ¦¡¢ÎïÖʽṹ֪ʶµÄ×ÛºÏÔËÓÃÄÜÁ¦¡£

½âÎö£º£¨1£©XÔ­×ÓµÄL²ãÉÏsµç×ÓÊýµÈÓÚpµç×ÓÊý£¬ËùÒÔXµÄºËÍâµç×ÓÅŲ¼ÊÇ1s22s22p2£¬ÎªCÔªËØ£»YÔ­×ÓºËÍâµÄL²ãÓÐ3¸öδ³É¶Ôµç×Ó£¬ËùÒÔYµÄºËÍâµç×ÓÅŲ¼ÊÇ1s22s22p3£¬ÎªNÔªËØ¡£ËùÒÔYµÄ¼Ûµç×ÓΪ2s22p3£¬¼Ûµç×ÓÅŲ¼Í¼Îª£»XµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª26µÄÇ⻯ÎïÊÇC2H2£¬·Ö×ÓÖаüº¬2¸ö̼Çâ¦Ò¼ü¡¢1¸ö̼̼¦Ò¼üºÍÁ½¸ö̼̼¦Ð¼ü£¬ËùÒÔ·Ö×ÓÖеĦҼüÓë¦Ð¼üµÄ¼üÊýÖ®±ÈΪ3:2¡£ÕýÈ·´ð°¸£º¡¢3:2¡££¨2£©µØ¿ÇÖк¬Á¿×î¶àµÄÊÇOÔªËØ£¬ËùÒÔZΪOÔªËØ¡£C¡¢N¡¢Oͬ´¦ÓÚµÚ¶þÖÜÆÚ£¬Ô­×ÓÐòÊýµÝÔö£¬Òò´ËC¡¢N¡¢OÈýÖÖÔªËص縺ÐÔµÝÔö¡£ÈýÖÖÔªËصĵÚÒ»µçÀëÄÜ×ÜÌåµÝÔö£¬ÓÉÓÚNÔªËصÄ2p3ÊÇÒ»ÖÖ°ëÂúµÄÑÇÎȶ¨×´Ì¬£¬µÚÒ»µçÀëÄܱÈC¡¢O¶¼¸ß£¬ËùÒÔµÚÒ»µçÀëÄÜ´óС˳ÐòΪN>O>C¡£ÕýÈ·´ð°¸£ºN>O>C¡¢O > N >C¡££¨3£©X¡¢ZÔªËØ·Ö±ðÓëÇâÔªËØÐγɵÄ×î¼òµ¥»¯ºÏÎï·Ö±ðÊÇCH4¡¢H2O£¬ÓÉÓÚH2O·Ö×Ó¼ä´æÔÚÇâ¼ü£¬ËùÒԷеã±ÈCH4¸ß¡£ÕýÈ·´ð°¸£ºH2O¡¢Ë®·Ö×Ó¼ä¿ÉÒÔÐγÉÇâ¼ü£¬Ê¹·ÐµãÉý¸ß¡££¨4£©XZÓëY2·Ö±ðÊÇCOºÍN2£¬¶þÕßÊôÓڵȵç×ÓÌ壬N2µÄ½á¹¹ÊÇ£¬ËùÒÔCOµÄ½á¹¹ÊÇ¡£ÕýÈ·´ð°¸£º¡££¨5£©0.01 mol RCl3¡¤6H2OÔÚË®ÈÜÒºÖÐÓùýÁ¿ÏõËáÒøÈÜÒº´¦Àí²úÉú0.02 mol AgCl³Áµí£¬ËùÒÔÅäºÏÎïRCl3¡¤6H2OµÄÍâ½çº¬ÓÐ2 ¸öCl-£¬Ôò´ËÅäºÏÎïÖ»¿ÉÄÜÊÇÑ¡ÏîÖеÄB¡£ÕýÈ·´ð°¸£ºB¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿Ä³Ñо¿ÐÔѧϰС×éΪÁËÖÆÈ¡¡¢ÊÕ¼¯´¿¾»¸ÉÔïµÄÂÈÆø²¢Ì½¾¿ÂÈÆøµÄÐÔÖÊ£¬ËûÃÇÉè¼ÆÁËÈçͼËùʾµÄʵÑé×°Öãº

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÕûÌ×ʵÑé×°ÖõÄÁ¬½Ó˳ÐòÊÇf½Ó(¡¡) (¡¡)½Ó(¡¡)(¡¡)½Ó(¡¡)(¸÷½Ó¿Ú´¦µÄ×Öĸ´úºÅ)¡£_________

£¨2£©E×°ÖÃÖÐÖÆÈ¡ÂÈÆøµÄÀë×Ó·½³ÌʽÊÇ_________________________¡£

£¨3£©B×°ÖõÄ×÷ÓÃÊÇ__________________£»A×°ÖÃÖÐÊÔ¼ÁXÊÇ________________¡£

£¨4£©C×°ÖÃÖпɹ۲쵽µÄÏÖÏóÊÇ____________¡£

£¨5£©ClO2ºÍÂÈÆø¾ßÓÐÏàËƵÄÐÔÖÊ£¬ÓÃÈçͼװÖÿÉÒԲⶨij»ìºÏÆøÖÐClO2 µÄº¬Á¿£º£¨ÆäËû³É·Ö²»²ÎÓë·´Ó¦£©

¢ñ.ÔÚ׶ÐÎÆ¿ÖмÓÈë×ãÁ¿µÄµâ»¯¼Ø£¬ÓÃ50 mLË®Èܽâºó£¬ÔÙ¼ÓÈë3 mLÏ¡ÁòË᣻

¢ò.ÔÚ²£Á§Òº·â×°ÖÃÖмÓÈëË®£¬Ê¹ÒºÃæû¹ý²£Á§Òº·â¹ÜµÄ¹Ü¿Ú£»

¢ó.½«Ò»¶¨Á¿µÄ»ìºÏÆøÌåͨÈë׶ÐÎÆ¿ÖÐÎüÊÕ£»

¢ô.½«²£Á§Òº·â×°ÖÃÖеÄË®µ¹Èë׶ÐÎÆ¿ÖУ»

¢õ.ÓÃ0.100 0 mol¡¤L£­1 Áò´úÁòËáÄƱê×¼ÈÜÒºµÎ¶¨×¶ÐÎÆ¿ÖеÄÈÜÒº(I2£«2S2O32£­=2I£­£«S4O62£­)£¬Ö¸Ê¾¼Á

ÏÔʾÖÕµãʱ¹²ÓÃÈ¥20.00 mLÁò´úÁòËáÄÆÈÜÒº¡£Ôڴ˹ý³ÌÖУº

A. ׶ÐÎÆ¿ÄÚClO2Óëµâ»¯¼Ø·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________________________¡£

B. ²âµÃ»ìºÏÆøÖÐClO2µÄÖÊÁ¿Îª________g¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø