ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÔڲⶨÁòËá;§ÌåÖнᾧˮº¬Á¿µÄʵÑé²Ù×÷ÖУº
£¨1£©¼ÓÈÈÇ°Ó¦½«¾§Ìå·ÅÔÚ__________ÖÐÑÐË飬¼ÓÈÈÊÇ·ÅÔÚ__________ÖнøÐУ¬¼ÓÈÈʧˮºó£¬Ó¦·ÅÔÚ__________ÖÐÀäÈ´¡£
£¨2£©ÅжÏÊÇ·ñÍêȫʧˮµÄ·½·¨ÊÇ______________________________________________¡£
£¨3£©ÏÂÃæÊÇijѧÉúÒ»´ÎʵÑéµÄÊý¾Ý£¬ÇëÍê³É¼ÆË㣬ÌîÈëÏÂÃæµÄ±í¸ñÖС£
ÛáÛöÖÊÁ¿ | ÛáÛöÓ뾧Ìå×ÜÖÊÁ¿ | ¼ÓÈȺóÛáÛöÓë¹ÌÌå×ÜÖÊÁ¿ | ²âµÃ¾§ÌåÖнᾧˮ¸öÊý |
11.7 g | 22.7 g | 17. 6 g | _________ |
£¨4£©Õâ´ÎʵÑéÖвúÉúÎó²îµÄÔÒò¿ÉÄÜÊÇ__________£¨Ìîд×Öĸ£©ËùÔì³É¡£
A£®ÁòËá;§ÌåÖк¬ÓÐÒ×»Ó·¢ÐÔÔÓÖ¾ B£®ÊµÑéÇ°¾§ÌåÒѲ¿·Ö±ä°×
C£®¼ÓÈÈʱ¹ÌÌ岿·Ö±äºÚ D£®¼ÓÈÈʧˮºó©ÖÃÔÚ¿ÕÆøÖÐÀäÈ´
£¨5£©ÒÑÖªÔÚÛáÛöÖмÓÈÈÁòËá;§Ì壬ÊÜÈÈ·Ö½â¹ý³ÌÈçÏ£º
CuSO4¡¤5H2O CuSO4¡¤3H2O CuSO4¡¤H2O CuSO4
ÓÐÈ˽èÖúÈçͼ·â±Õ×°ÖýøÐÐÁòËá;§ÌåÍÑˮʵÑ飬»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù±¾ÊµÑé¿ÉÓÃÓÚÑéÖ¤µÄ»¯Ñ§¶¨ÂÉÊÇ_____________________________¡£
¢Úa´¦¼ÓÈÈƬ¿ÌºóÏÖÏó£º______________________________________¡£
¢ÛÄãÈÏΪ´Ë×°ÖÃÉè¼ÆÊÇ·ñºÏÀí£®¿Æѧ£¿Èç²»ºÏÀí£¬Çëд³öÀíÓÉ£º___________________________________________________________________________________________________¡£
¡¾´ð°¸¡¿Ñв§ ÛáÛö ¸ÉÔïÆ÷ ÈôÁ¬ÐøÁ½´Î¼ÓÈȵÄÖÊÁ¿²î²»³¬¹ý0.1 g£¬Ôò˵Ã÷Íêȫʧˮ 7.7 ACD ÖÊÁ¿Êغ㶨ÂÉ À¶É«¾§Ìå±äΪ°×É«·Û ²»ºÏÀí£»·â±ÕÒÇÆ÷²»Ò˼ÓÈÈ¡£
¡¾½âÎö¡¿
ÁòËá;§ÌåÖнᾧˮµÄÖÊÁ¿·ÖÊý£½(½á¾§Ë®µÄÖÊÁ¿=ÁòËá;§ÌåºÍ´ÉÛáÛöµÄÖÊÁ¿¡ªÎÞË®ÁòËáͺʹÉÛáÛöµÄÖÊÁ¿ )¡£²½ÖèΪ¢ÙÑÐÄ¥£ºÔÚÑв§Öн«ÁòËá;§ÌåÑÐËé¡£¢Ú³ÆÁ¿£»×¼È·³ÆÁ¿¸ÉÔïµÄ´ÉÛáÛöµÄÖÊÁ¿£¬²¢ÓôËÛáÛö׼ȷ³ÆÈ¡Ò»¶¨ÖÊÁ¿ÒÑÑÐËéµÄÁòËá;§Ìå¡£¢Û¼ÓÈÈ£º¼ÓÈȾ§Ì壬ʹÆäʧȥȫ²¿½á¾§Ë®(ÓÉÀ¶É«ÍêÈ«±äΪ°×É«)¡£¢Ü³ÆÁ¿£ºÔÚ¸ÉÔïÆ÷ÄÚÀäÈ´ºó³ÆÁ¿£¬²¢¼ÇÏ´ÉÛáÛöºÍÎÞË®ÁòËá͵ÄÖÊÁ¿¡£¢ÝÔÙ¼ÓÈÈ¡¢ÔÙ³ÆÁ¿ÖÁºãÖØ£º°ÑÊ¢ÓÐÎÞË®ÁòËá͵ĴÉÛáÛöÔÙ¼ÓÈÈ£¬ÔÙ·ÅÈë¸ÉÔïÆ÷ÀïÀäÈ´ºóÔÙ³ÆÁ¿£¬¼ÇÏÂÖÊÁ¿¡£µ½Á¬ÐøÁ½´Î³ÆÁ¿µÄÖÊÁ¿Ïà²î²»³¬¹ý0.1gΪֹ¡£¢Þ¼ÆË㣺¸ù¾ÝʵÑé²âµÃµÄ½á¹ûÇóÁòËá;§ÌåÖнᾧˮµÄÖÊÁ¿·ÖÊý¡£
£¨1£©¼ÓÈÈÇ°Ó¦½«¾§Ìå·ÅÔÚÑв§ÖÐÑÐË飬¼ÓÈÈÊÇ·ÅÔÚÛáÛöÖнøÐУ¬¼ÓÈÈʧˮºó£¬Ó¦·ÅÔÚ¸ÉÔïÆ÷ÖÐÀäÈ´¡£
£¨2£©ÅжÏÊÇ·ñÍêȫʧˮµÄ·½·¨ÊÇÈôÁ¬ÐøÁ½´Î¼ÓÈȵÄÖÊÁ¿²î²»³¬¹ý0.1 g£¬Ôò˵Ã÷Íêȫʧˮ¡£
£¨3£©½á¾§Ë®µÄÖÊÁ¿=ÁòËá;§ÌåºÍ´ÉÛáÛöµÄÖÊÁ¿¡ªÎÞË®ÁòËáͺʹÉÛáÛöµÄÖÊÁ¿=22.7g-17.6g=5.1g£¬½á¾§Ë®µÄ¸öÊý= £»
£¨4£©A£®ÁòËá;§ÌåÖк¬ÓÐÒ×»Ó·¢ÐÔÔÓÖ¾£¬µ¼Ö¼ÓÈȹý³ÌÖйÌÌå¼õÉÙÁ¿Ôö¶à£¬²â¶¨½á¹ûÆ«´ó£¬AÕýÈ·£»
B£®ÊµÑéÇ°¾§ÌåÒѲ¿·Ö±ä°×¶ÔʵÑé²»Ó°Ï죬B´íÎó£»
C£®¼ÓÈÈʱ¹ÌÌ岿·Ö±äºÚ£¬ËµÃ÷CuSO4ÒÑ·¢Éú·Ö½âCuSO4CuO+SO3¡ü£¬Ê¹²â¶¨µÄ½á¹ûÆ«´ó£¬CÕýÈ·£»
D£®¼ÓÈÈʧˮºó©ÖÃÔÚ¿ÕÆøÖÐÀäÈ´£¬¹ÌÌåÎüÊÕ¿ÕÆøÖеÄË®£¬ÊǹÌÌå¼õÉٵIJîÖµ½µµÍ£¬²â¶¨½á¹ûƫС£¬DÕýÈ·¡£
´ð°¸ÎªACD¡£
£¨5£©·â±Õ×°ÖýøÐÐÁòËá;§ÌåÍÑˮʵÑ飬¢ÙʵÑéÖÐÎïÖʲ»»áɢʧ£¬±¾ÊµÑé¿ÉÓÃÓÚÑéÖ¤µÄ»¯Ñ§¶¨ÂÉÊÇÖÊÁ¿Êغ㶨ÂÉ¡£
¢Úa´¦¼ÓÈÈƬ¿Ìºó£¬½á¾§Ë®·Ö½â£¬ÏÖÏóΪÀ¶É«¾§Ìå±äΪ°×É«·Û£»
¢Û´Ë×°Öò»ºÏÀí£¬·â±ÕÒÇÆ÷²»Ò˼ÓÈÈ¡£
¡¾ÌâÄ¿¡¿½«0.20 mol/LµÄÑÎËáºÍÎïÖʵÄÁ¿Å¨¶ÈΪc mol/LµÄNaOHÈÜÒº°´²»Í¬Ìå»ý±ÈÅäÖƳÉÁ½ÖÖÈÜÒº¡£Ï±íÊÇÅäÖÆʱËùÈ¡ÑÎËáÓë NaOH ÈÜÒºÌå»ýÓë»ìºÏºóÈÜÒºÖÐNa+ÓëCl-µÄÎïÖʵÄÁ¿Å¨¶ÈÊý¾Ý£¨ºöÂÔÈÜÒºÌå»ý±ä»¯£©£º
ÈÜÒº | »ìºÏÇ°ËùÈ¡ÈÜÒºÌå»ý£¨mL£© | »ìºÏºóÀë×ÓŨ¶È£¨mol/L£© | ||
HCl | NaOH | Na+ | Cl- | |
¢Ù | 30 | x | 1.5z | z |
¢Ú | 10 | y | z | 2z |
ÏÂÁÐ˵·¨ÕýÈ·£¨ £©
A.x=90B.y=30C.z=0.10D.c=0.10