ÌâÄ¿ÄÚÈÝ
11£®Ä³Ñо¿Ð¡×éΪÁË̽¾¿Ò»ÖÖÎÞ»ú¿óÎïÖÊX£¨½öº¬ËÄÖÖÔªËØ£©µÄ×é³ÉºÍÐÔÖÊ£¬Éè¼Æ²¢Íê³ÉÈçÏÂʵÑ飺ʵÑéÒ»¡¢¶¨ÐԲⶨ£ºÓÃÈçͼ1×°Öòⶨ¿óÎïXÖеÄÔªËØ
£¨1£©¼ÓÈÈÒ»¶Îʱ¼äºó¹Û²ìµ½ÏÖÏó£ºCuSO4¹ÌÌåÓÉ°×É«±äΪÀ¶É«£¬³ÎÇåʯ»ÒË®±ä»ë×Ç£¬ËµÃ÷X·Ö½âÉú³ÉÁËCO2ºÍH2O£®
£¨2£©È¡·Ö½âºóµÄ¹ÌÌåÉÙÁ¿£¬¼ÓÈëÏ¡ÑÎËáºó¹ÌÌåÈܽâµÃµ½À¶É«ÈÜÒº£®
¾ÝÒÔÉÏÊÂʵ֤Ã÷XÖеÄËÄÖÖÔªËØ·Ö±ðÊÇCu¡¢H¡¢C¡¢O£®
ʵÑé¶þ¡¢¶¨Á¿²â¶¨£ºÍ¨¹ýͼ2ËùʾװÖõÄÁ¬½Ó£¬½øÐж¨Á¿·ÖÎöÀ´²â¶¨Æä×é³É£®
£¨3£©ÊµÑ鿪ʼʱҪͨÈë¹ýÁ¿µÄ¿ÕÆø£¬Æä×÷ÓÃÊÇÅž»¿ÕÆøÖÐCO2ºÍË®ÕôÆø£®
£¨4£©¸÷×°ÖõĽӿÚ˳ÐòÊÇ£ºa¡úf¡úg¡úh¡úi¡úb¡úc¡úd£®
£¨5£©×°ÖÃC·ÅÔÚ×îºóµÄ×÷ÓÃÊÇ·ÀÖ¹¿ÕÆøÖеÄCO2ºÍË®ÕôÆø½øÈ룬ӰÏì²â¶¨½á¹û£®
£¨6£©ÊµÑé¹ý³ÌÖгÆÈ¡¿óÎïXµÄÖÊÁ¿Îª11.1¿Ë£¬·´Ó¦½áÊøºó×°ÖÃBÖÊÁ¿Ôö¼ÓÁË2.2¿Ë£¬E×°ÖÃÔöÖØ0.9¿Ë£¬Ôò¿óÎïXµÄ»¯Ñ§Ê½Îª£ºCu2£¨OH£©2CO3£®
·ÖÎö I¡¢£¨1£©ÎÞË®ÁòËáͱäÀ¶ËµÃ÷ÓÐË®£¬³ÎÇåʯ»ÒË®±ä»ë×Ç£¬ËµÃ÷ÓжþÑõ»¯Ì¼£»
£¨2£©·Ö½âºóµÄ¹ÌÌåÉÙÁ¿£¬¼ÓÈëÏ¡ÑÎËáºó¹ÌÌåÈܽâµÃµ½À¶É«ÈÜÒº£¬ËµÃ÷ÓÐÂÈ»¯ÍÈÜÒºÉú³É£¬½áºÏ£¨1£©ÅжÏÔªËØ×é³É£»
II¡¢°Ñ¿ÕÆøÏÈͨ¹ý¼îʯ»Ò£¬³öµô¿ÕÆøÖеĶþÑõ»¯Ì¼ºÍË®ÕôÆø£¬È»ºóͨÈëÕû¸ö×°Öã¬ÒÔÅž»×°ÖÃÖÐÔÓеĿÕÆø£¬ÔÚ¼ÓÈÈÌõ¼þÏÂÑùÆ··Ö½â£¬Éú³ÉµÄ»ìºÏÆøÌ壬ͨ¹ýŨÁòËáÎüÊÕË®£¬ÔÙͨ¹ýB¼îʯ»ÒÎüÊÕ¶þÑõ»¯Ì¼£¬×îºóÁ¬½ÓC£¬ÒÔ·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆøºÍ¶þÑõ»¯Ì¼½øÈëBÖвúÉú¸ÉÈÅ£»
£¨3£©ÏÈͨ¹ýÁ¿¿ÕÆøÅųö×°ÖÃÖÐÔÓеĿÕÆø£»
£¨4£©¸ù¾ÝʵÑé¹ý³Ì·ÖÎöÅжÏÒÇÆ÷Á¬½Ó˳Ðò£»
£¨5£©¿ÕÆøÖеĶþÑõ»¯Ì¼ºÍË®ÕôÆø½øÈëBÖлáʹ²âµÃµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Æ«´ó£»
£¨6£©·´Ó¦½áÊøºó×°ÖÃBÖÊÁ¿Ôö¼ÓÁË2.2¿Ë£¬¼´Éú³ÉµÄ¶þÑõ»¯Ì¼Îª2.2g£¬E×°ÖÃÔöÖØ0.9¿Ë£¬¼´Éú³ÉˮΪ0.9g£¬¸ù¾ÝÔªËØÊغã¼ÆËãC¡¢H¡¢O¡¢CuµÄÎïÖʵÄÁ¿£¬¾Ý´ËÈ·¶¨»¯Ñ§Ê½£®
½â´ð ½â£ºI¡¢£¨1£©ÎÞË®ÁòËáͱäÀ¶ËµÃ÷ÓÐË®£¬³ÎÇåʯ»ÒË®±ä»ë×Ç£¬ËµÃ÷ÓжþÑõ»¯Ì¼£¬ËùÒÔX·Ö½âÉú³ÉÁËCO2ºÍ£»
¹Ê´ð°¸Îª£ºCO2£»H2O£»
£¨2£©ÓÉ£¨1£©·ÖÎö¿ÉÖªX·Ö½âÉú³É¶þÑõ»¯Ì¼ºÍË®£¬ÔòXÖк¬ÓÐC¡¢H¡¢OÔªËØ£¬·Ö½âºóµÄ¹ÌÌåÉÙÁ¿£¬¼ÓÈëÏ¡ÑÎËáºó¹ÌÌåÈܽâµÃµ½À¶É«ÈÜÒº£¬ËµÃ÷ÓÐÂÈ»¯ÍÈÜÒºÉú³É£¬ÔòXÖл¹º¬ÓÐCuÔªËØ£¬ËùÒÔXÖÐÔªËØ×é³ÉΪCu¡¢H¡¢C¡¢O£»
¹Ê´ð°¸Îª£ºCu¡¢H¡¢C¡¢O£»
II¡¢°Ñ¿ÕÆøÏÈͨ¹ý¼îʯ»Ò£¬³öµô¿ÕÆøÖеĶþÑõ»¯Ì¼ºÍË®ÕôÆø£¬È»ºóͨÈëÕû¸ö×°Öã¬ÒÔÅž»×°ÖÃÖÐÔÓеĿÕÆø£¬ÔÚ¼ÓÈÈÌõ¼þÏÂÑùÆ··Ö½â£¬Éú³ÉµÄ»ìºÏÆøÌ壬ͨ¹ýŨÁòËáÎüÊÕË®£¬ÔÙͨ¹ýB¼îʯ»ÒÎüÊÕ¶þÑõ»¯Ì¼£¬×îºóÁ¬½ÓC£¬ÒÔ·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆøºÍ¶þÑõ»¯Ì¼½øÈëBÖвúÉú¸ÉÈÅ£»
£¨3£©×°ÖÃÖÐÓпÕÆø£¬ÆäÖеĶþÑõ»¯Ì¼ºÍË®ÕôÆø¶ÔʵÑéÓиÉÈÅ£¬ËùÒÔʵÑ鿪ʼʱҪͨÈë¹ýÁ¿µÄ¿ÕÆø£¬Åž»¿ÕÆøÖÐCO2ºÍË®ÕôÆø£»
¹Ê´ð°¸Îª£ºÅž»¿ÕÆøÖÐCO2ºÍË®ÕôÆø£»
£¨4£©ÓÉ·ÖÎö¿É֪װÖõÄÁ¬½Ó˳ÐòΪ£ºa¡úf¡úg¡úh¡úi¡úb¡úc£»
¹Ê´ð°¸Îª£ºf¡¢g¡¢h¡¢i¡¢b¡¢c£»
£¨5£©¿ÕÆøÖеĶþÑõ»¯Ì¼ºÍË®ÕôÆø½øÈëBÖлáʹ²âµÃµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Æ«´ó£¬ËùÒÔB×°ÖúóÃæÁ¬½ÓÒ»¸öÊ¢Óмîʯ»ÒµÄ¸ÉÔï¹ÜC£¬·ÀÖ¹¿ÕÆøÖеÄCO2ºÍË®ÕôÆø½øÈ룬ӰÏì²â¶¨½á¹û£»
¹Ê´ð°¸Îª£º·ÀÖ¹¿ÕÆøÖеÄCO2ºÍË®ÕôÆø½øÈ룬ӰÏì²â¶¨½á¹û£»
£¨6£©·´Ó¦½áÊøºó×°ÖÃBÖÊÁ¿Ôö¼ÓÁË2.2¿Ë£¬¼´Éú³ÉµÄ¶þÑõ»¯Ì¼Îª2.2g£¬Ôòn£¨CO2£©=n£¨C£©=$\frac{2.2g}{44g/mol}$=0.05mol£¬
E×°ÖÃÔöÖØ0.9¿Ë£¬¼´Éú³ÉˮΪ0.9g£¬Ôòn£¨H£©=2n£¨H2O£©=$\frac{0.9g}{18g/mol}$¡Á2=0.1mol£¬
Óɶ¨ÐÔ·ÖÎö¿ÉÖª£º·Ö½âºóµÄ¹ÌÌåÉÙÁ¿£¬¼ÓÈëÏ¡ÑÎËáºó¹ÌÌåÈܽâµÃµ½À¶É«ÈÜÒº£¬Ôò·Ö½âºóµÄ¹ÌÌåΪCuO£¬ÔòCuOµÄÖÊÁ¿Îª11.1g-2.2g-0.9g=8.0g£¬
ËùÒÔn£¨CuO£©=$\frac{8.0g}{80g/mol}$=0.1mol£¬
ÑùÆ·ÖÐOÔªËصÄÎïÖʵÄÁ¿£ºn£¨O£©=0.05¡Á2+0.05+0.1=0.25mol£¬
ÔòÑùÆ·ÖÐN£¨Cu£©£ºN£¨H£©£ºN£¨C£©£ºN£¨O£©=0.1mol£º0.05mol£º0.1mol£º0.25mol=2£º1£º2£º5£¬ÔòÆ仯ѧʽΪCu2£¨OH£©2CO3£»
¹Ê´ð°¸Îª£ºCu2£¨OH£©2CO3£®
µãÆÀ ±¾Ì⿼²éÁËÎïÖÊ»¯Ñ§Ê½µÄÈ·¶¨£¬Éæ¼°ÎïÖʵļìÑé¡¢ÎïÖʵÄÐÔÖÊ¡¢Ô×ÓÊغãÔÚ¼ÆËãÖеÄÓ¦ÓõÈ֪ʶµã£¬ÊìϤԪËØ»¯ºÏÎïµÄÐÔÖÊÊǽⱾÌâ¹Ø¼ü£¬Ã÷°×ʵÑéÔÀíÒÔ¼°ÊµÑé×°ÖõÄÁ¬½Ó˳ÐòºÍÿһ²½·¢ÉúµÄ·´Ó¦¼°·´Ó¦ÏÖÏóÊǽâÌâµÄ¹Ø¼ü£¬ÌâÄ¿ÄѶÈÖеȣ®
A£® | ¸Ãµç³ØÖÐͨÈë¼×´¼µÄµç¼«ÎªµçÔ´µÄÕý¼« | |
B£® | ÑõÆø±»»¹Ô | |
C£® | µ±µ¼ÏßÖÐͨ¹ý4molµç×Óʱ£¬ÏûºÄ¼×´¼µÄÎïÖʵÄÁ¿Îª1mol | |
D£® | ÈÜÒºÖеÄH+Ïòͨ¼×´¼µÄµç¼«Ô˶¯ |
A£® | C2H6ºÍC4H10 | B£® | C3H8ºÍC5H10 | C£® | C6H6ºÍC6H12 | D£® | CH4ºÍC2H2 |
A£® | Ö÷×åÔªËØ·Ö²¼ÓÚ¶ÌÖÜÆںͳ¤ÖÜÆÚÀ¶ø¸±×åÔªËؽö·Ö²¼ÓÚ³¤ÖÜÆÚÀï | |
B£® | ÔªËØÖÜÆÚ±íÖУ¬Î»ÓÚͬһÖ÷×åµÄÔªËصÄÔ×Ó×îÍâ²ãµç×ÓÊýÏàͬ£¬ÇÒµÈÓÚ×åÐòÊý | |
C£® | ÔªËØÖÜÆÚ±íÖУ¬ÖÜÆÚµÄÐòÊý¾ÍÊǸÃÖÜÆÚÔªËØÔ×Ó¾ßÓеĵç×Ó²ãÊý | |
D£® | ÔªËØÖÜÆÚ±íÓÐ7¸öºáÐУ¬7¸öÖÜÆÚ£»18¸ö×ÝÁУ¬18¸ö×å |
A£® | 2 mL 0.5 mol/L¹èËáÄÆÈÜÒºÖеÎÈëÑÎËáËùÖƵõĹèËὺÌåÖУ¬º¬½ºÁ£ÊýĿΪ0.001NA | |
B£® | 8.4 g NaHCO3¹ÌÌåÖк¬ÓеÄÀë×Ó×ÜÊýΪ0.3NA | |
C£® | 25¡æʱ£¬1 L pH=lµÄCH3COOHÈÜÒºÖк¬ÓÐH+ÊýĿΪ0£®lNA | |
D£® | 7.8 g Na2O2¹ÌÌåÖк¬ÓеĹ²Óõç×Ó¶ÔÊýĿΪ0.2NA |
A£® | ×î¼òµ¥Æø̬Ç⻯ÎïµÄÈÈÎȶ¨ÐÔ£ºR£¾Q | |
B£® | ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄËáÐÔ£ºQ£¼W | |
C£® | Ô×Ӱ뾶£ºT£¾Q£¾R | |
D£® | TµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïÈÜÒºÒ»¶¨ÏÔ¼îÐÔ |
A£® | µÚÈýÖÜÆÚ¢öA×å | B£® | µÚ¶þÖÜÆÚ¢öA×å | C£® | µÚÈýÖÜÆÚ¢ôA×å | D£® | µÚ¶þÖÜÆÚ¢ôA×å |