题目内容
如图,在Rt△ABC中,∠ACB=90°,AB=5,BC=3,BE平分∠ABC,DE⊥AB,垂足为D,那么AE+ED= 
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4
试题分析:∵在Rt△ABC中,∠ACB=90°,AB=5,BC=3,∴AC=

∵∠ACB=90°,∴EC⊥BC,又BE平分∠ABC,DE⊥AB,∴DE=CE,又AC=4,∴AE+DE=AE+CE=AC=4.
点评:熟练掌握角平分线上的点到角两边的距离相等是解本题的关键.
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