题目内容
如图,
为
的直径,
为
的弦,,则为
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A.37° | B.![]() | C.![]() | D.![]() |
A
分析:连接AC,由AB是直径,可得直角,根据同弧所对的圆周角相等,可得∠ACD的度数,利用两角差可得答案.
解答:解:连接AC,
∵AB是圆的直径,
∴∠BCA=90°,
又∠ACD=∠ABD=53°,
∴∠BCD=∠ACB-∠ACD=90°-53°=37°.
故选A.
点评:本题考查了圆周角定理;直径在题目已知中出现时,往往要利用其所对的圆周角是直角这一结论,做题时注意应用,连接AC是正确解答本题的关键.
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