题目内容
如图,在梯形ABCD中,AD∥BC,且AD=3,BC=9,则S△AOD:S△BOC为( )
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A.1:3 | B.1:9 | C.1:
| D.2:5 |

∵AD∥BC
∴△AOD∽△COB
∴S△AOD:S△BOC=(AD:BC)2=1:9.
故选B.
∴△AOD∽△COB
∴S△AOD:S△BOC=(AD:BC)2=1:9.
故选B.
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题目内容
A.1:3 | B.1:9 | C.1:
| D.2:5 |