题目内容
(1)在Rt△ABC中,已知:∠C=90°,AC=2,BC=
,求∠A的正弦值.
(2)计算sin245°+cos245°-tan30°×sin60°.
5 |
(2)计算sin245°+cos245°-tan30°×sin60°.
(1)∵AC=2,BC=
,
∴AB=
=3,
∴sinA=
=
;
(2)sin245°+cos245°-tan30°×sin60°
=1+1-
×
=2-
=1
.
5 |
∴AB=
22+
|
∴sinA=
BC |
AB |
| ||
3 |
(2)sin245°+cos245°-tan30°×sin60°
=1+1-
| ||
3 |
| ||
2 |
=2-
1 |
2 |
=1
1 |
2 |
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