题目内容
计算:
(1)
-
(2)
÷
•(a+3)
(3)
+
-
(4)(2-
)2-(2+
)(2-
)+
.
(1)
a2 |
a+3 |
9 |
a+3 |
(2)
2a-4 |
a2+6a+9 |
a-2 |
a+3 |
(3)
27 |
|
2 | ||
|
(4)(2-
3 |
3 |
3 |
1 | ||
|
(1)原式=
=
=a-3;
(2)原式=
•
•(a+3)
=2;
(3)原式=3
+
-
=
-
;
(4)原式=4-2
+3-(4-3)+2-
=4-2
+3-1+2-
=8-3
.
a2-9 |
a+3 |
=
(a+3)(a-3) |
a+3 |
=a-3;
(2)原式=
2(a-2) |
(a+3)2 |
a+3 |
a-2 |
=2;
(3)原式=3
3 |
| ||
3 |
2 |
=
10
| ||
3 |
2 |
(4)原式=4-2
3 |
3 |
=4-2
3 |
3 |
=8-3
3 |
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