题目内容
4
×1
+45×
(1+0.78×
)÷(145+
)
6.5+3.5÷0.5×5.2
8400+108×42
[2
+2.4×(1
-1.5)]÷1.1
(12+999+99)÷[56×(
-
)].
| 1 |
| 2 |
| 1 |
| 3 |
| 5 |
| 9 |
(1+0.78×
| 5 |
| 6 |
| 3 |
| 4 |
6.5+3.5÷0.5×5.2
8400+108×42
[2
| 3 |
| 5 |
| 2 |
| 3 |
(12+999+99)÷[56×(
| 3 |
| 7 |
| 3 |
| 8 |
分析:(1)同时两个运算乘法,再算加法;
(2)先算第一个小括号里面的乘法,再同时运算第一个小括号里面的加法和第二个小括号里面的加法,最后算括号外的除法;
(3)先算除法,再算乘法,最后算加法;
(4)先算乘法,再算加法;
(5)先算小括号里面的减法,再算中括号里面的乘法,然后算中括号里面的加法,最后算括号外的除法;
(6)第一个小括号里面运用凑整法简算,中括号里面运用乘法分配律简算,最后算除法.
(2)先算第一个小括号里面的乘法,再同时运算第一个小括号里面的加法和第二个小括号里面的加法,最后算括号外的除法;
(3)先算除法,再算乘法,最后算加法;
(4)先算乘法,再算加法;
(5)先算小括号里面的减法,再算中括号里面的乘法,然后算中括号里面的加法,最后算括号外的除法;
(6)第一个小括号里面运用凑整法简算,中括号里面运用乘法分配律简算,最后算除法.
解答:解:(1)4
×1
+45×
,
=6+25,
=31;
(2)(1+0.78×
)÷(145+
),
=(1+
)÷(145+
),
=1
÷145
,
=
;
(3)6.5+3.5÷0.5×5.2,
=6.5+7×5.2,
=6.5+36.4,
=42.9;
(4)8400+108×42,
=8400+4536,
=12936;
(5)[2
+2.4×(1
-1.5)]÷1.1,
=[2
+2.4×
]÷1.1,
=[2.6+0.4]÷1.1,
=3÷1.1,
=
;
(6)(12+999+99)÷[56×(
-
)],
=(12+1000+100-2)÷[56×
-56×
],
=[1000+100+(12-2)]÷[24-21],
=(1000+100+10)÷3,
=1110÷3,
=370.
| 1 |
| 2 |
| 1 |
| 3 |
| 5 |
| 9 |
=6+25,
=31;
(2)(1+0.78×
| 5 |
| 6 |
| 3 |
| 4 |
=(1+
| 13 |
| 20 |
| 3 |
| 4 |
=1
| 13 |
| 20 |
| 3 |
| 4 |
=
| 3 |
| 265 |
(3)6.5+3.5÷0.5×5.2,
=6.5+7×5.2,
=6.5+36.4,
=42.9;
(4)8400+108×42,
=8400+4536,
=12936;
(5)[2
| 3 |
| 5 |
| 2 |
| 3 |
=[2
| 3 |
| 5 |
| 1 |
| 6 |
=[2.6+0.4]÷1.1,
=3÷1.1,
=
| 30 |
| 11 |
(6)(12+999+99)÷[56×(
| 3 |
| 7 |
| 3 |
| 8 |
=(12+1000+100-2)÷[56×
| 3 |
| 7 |
| 3 |
| 8 |
=[1000+100+(12-2)]÷[24-21],
=(1000+100+10)÷3,
=1110÷3,
=370.
点评:本题考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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