题目内容
计算:
(1+
)×(1+
)×(1+
)×(1+
)×…×(1+
)×(1+
);
(1-
)×(1-
)×(1-
)×(1-
)×…×(1-
)×(1-
).
(1+
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 9 |
| 1 |
| 10 |
(1-
| 1 |
| 10 |
| 1 |
| 9 |
| 1 |
| 8 |
| 1 |
| 7 |
| 1 |
| 3 |
| 1 |
| 2 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:(1)先求出括号里面的数是多少,再根据分数乘法的计算方法,先约分,再计算即可;
(2)先求出括号里面的数是多少,再根据分数乘法的计算方法,先约分,再计算即可.
(2)先求出括号里面的数是多少,再根据分数乘法的计算方法,先约分,再计算即可.
解答:
解:(1)(1+
)×(1+
)×(1+
)×(1+
)×…×(1+
)×(1+
)
=
×
×
×
×…×
×
=
;
(2)(1-
)×(1-
)×(1-
)×(1-
)×…×(1-
)×(1-
)
=
×
×
×
×…×
×
=
.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 9 |
| 1 |
| 10 |
=
| 3 |
| 2 |
| 4 |
| 3 |
| 5 |
| 4 |
| 6 |
| 5 |
| 10 |
| 9 |
| 11 |
| 10 |
=
| 11 |
| 2 |
(2)(1-
| 1 |
| 10 |
| 1 |
| 9 |
| 1 |
| 8 |
| 1 |
| 7 |
| 1 |
| 3 |
| 1 |
| 2 |
=
| 9 |
| 10 |
| 8 |
| 9 |
| 7 |
| 8 |
| 6 |
| 7 |
| 2 |
| 3 |
| 1 |
| 2 |
=
| 1 |
| 10 |
点评:本题的重点是求出括号里面的数,再根据分数乘法的计算方法,先约分,再计算.
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