题目内容
(1+
)×(1+
)×(1+
)×…(1+
)×(1-
)×(1-
)×…×(1-
)= .
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考点:分数的巧算
专题:计算问题(巧算速算)
分析:根据乘法交换律和乘法结合律计算即可.
解答:
解:(1+
)×(1+
)×(1+
)×…(1+
)×(1-
)×(1-
)×…×(1-
)
=[(1+
)×(1-
)]×[((1+
)×(1-
)]×[(1+
)×(1-
)]×[(1+
)×(1-
)]×[(1+
)×(1-
)]
=[
×
]×[
×
]×[
×
]×[
×
]×[
×
]
=1×1×1×1×1
=1
故答案为:1.
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=[(1+
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=[
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=1×1×1×1×1
=1
故答案为:1.
点评:此题主要考查了乘法运算定律在分数四则混合运算中的应用.
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