题目内容
求未知数x
①
×-
=
②8x一7×2.3=32.9.
①
| 3 |
| 4 |
| 3 |
| 8 |
| 3 |
| 4 |
②8x一7×2.3=32.9.
分析:①根据等式的性质,两边同加上
,得
x=
,两边再同除以
即可;
②先求出7×2.3=16.1,原式变为8x-16.1=32.9,根据等式的性质,两边同加上16.1,再同除以8即可.
| 3 |
| 8 |
| 3 |
| 4 |
| 9 |
| 8 |
| 3 |
| 4 |
②先求出7×2.3=16.1,原式变为8x-16.1=32.9,根据等式的性质,两边同加上16.1,再同除以8即可.
解答:解:①
x-
=
,
x-
+
=
+
,
x=
,
x÷
=
÷
,
x=
×
,
x=
;
②8x-7×2.3=32.9,
8x-16.1=32.9,
8x-16.1+16.1=32.9+16.1,
8x=49,
8x÷8=49÷8,
x=
.
| 3 |
| 4 |
| 3 |
| 8 |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 8 |
| 3 |
| 8 |
| 3 |
| 4 |
| 3 |
| 8 |
| 3 |
| 4 |
| 9 |
| 8 |
| 3 |
| 4 |
| 3 |
| 4 |
| 9 |
| 8 |
| 3 |
| 4 |
x=
| 9 |
| 8 |
| 4 |
| 3 |
x=
| 3 |
| 2 |
②8x-7×2.3=32.9,
8x-16.1=32.9,
8x-16.1+16.1=32.9+16.1,
8x=49,
8x÷8=49÷8,
x=
| 49 |
| 8 |
点评:此题考查了根据等式的性质解方程,即方程两边同加、同减、同乘或同除以某数(0除外),方程的左右两边仍相等;注意“=”号上下要对齐.
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