题目内容
计算:
[5-3
÷(1
+2
×
)]÷
= .
[5-3
| 7 |
| 8 |
| 5 |
| 6 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 8 |
考点:整数、分数、小数、百分数四则混合运算
专题:运算顺序及法则
分析:先算小括号内的乘法,然后算小括号内的加法,然后算中括号内的除法,再算中括号内的减法,最后算括号外的除法.
解答:
解:[5-3
÷(1
+2
×
)]÷
=[5-3
÷(1
+
×
)]÷
=[5-3
÷(1
+
)]÷
=[5-
÷
]÷
=[5-
]÷
=
×8
=28
故答案为:28.
| 7 |
| 8 |
| 5 |
| 6 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 8 |
=[5-3
| 7 |
| 8 |
| 5 |
| 6 |
| 9 |
| 4 |
| 1 |
| 3 |
| 1 |
| 8 |
=[5-3
| 7 |
| 8 |
| 5 |
| 6 |
| 3 |
| 4 |
| 1 |
| 8 |
=[5-
| 31 |
| 8 |
| 31 |
| 12 |
| 1 |
| 8 |
=[5-
| 3 |
| 2 |
| 1 |
| 8 |
=
| 7 |
| 2 |
=28
故答案为:28.
点评:此题考查了分数的四则混合运算,注意运算顺序和运算法则.
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