题目内容
等比数列扩倍与错位相减:巧算1-
-
-
-…-
= .
| 4 |
| 5 |
| 4 |
| 25 |
| 4 |
| 125 |
| 4 |
| 5100 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:将1-
-
-
-…-
乘以5,得到5-4-
-
-…-
,再两式相减后除以4,即可得到结果.
| 4 |
| 5 |
| 4 |
| 25 |
| 4 |
| 125 |
| 4 |
| 5100 |
| 4 |
| 5 |
| 4 |
| 25 |
| 4 |
| 599 |
解答:
解:1-
-
-
-…-
,
=[(1-
-
-
-…-
)×5-(1-
-
-
-…-
)]÷4,
=[5-4-
-
-…-
-1+
+
+…+
+
]÷4,
=[5-4-1+
]÷4,
=
÷4,
=
.
故答案为:
.
| 4 |
| 5 |
| 4 |
| 25 |
| 4 |
| 125 |
| 4 |
| 5100 |
=[(1-
| 4 |
| 5 |
| 4 |
| 25 |
| 4 |
| 125 |
| 4 |
| 5100 |
| 4 |
| 5 |
| 4 |
| 25 |
| 4 |
| 125 |
| 4 |
| 5100 |
=[5-4-
| 4 |
| 5 |
| 4 |
| 25 |
| 4 |
| 599 |
| 4 |
| 5 |
| 4 |
| 25 |
| 4 |
| 599 |
| 4 |
| 5100 |
=[5-4-1+
| 4 |
| 5100 |
=
| 4 |
| 5100 |
=
| 1 |
| 5100 |
故答案为:
| 1 |
| 5100 |
点评:考查了分数的巧算,本题关键是掌握等比数列扩倍与错位相减的方法进行巧算.
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