摘要:(1) = . = .(2)推算OA10的长.
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OA1=1; OA2=
| 12+12 |
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| 1 |
| 2 |
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OA3=
| 2+12 |
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| 1 |
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| 2 |
OA4=
| 3+12 |
| 4 |
| 1 |
| 2 |
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| 2 |
…
问:(1)推算OA10的长度.
(2)推算:S10的值.
(3)求OAn的长度(用含n的代数式表示)
(
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(
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(
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(1)请用含n(n是正整数)的等式表示上述变化规律;
(2)推算出OA10的长;
(3)求出S12+S22+S22+…+S102的值. 查看习题详情和答案>>
OA22=(
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OA32=12+(
| 2 |
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OA42=12+(
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| 2 |
…
(1)推算出OA10的长;
(2)若一个三角形的面积是
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