摘要:1120 14. 15.40 16.12
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观察不等式:
•1≥
•
,
(1+
)≥
(
+
),
(1+
+
)≥
(
+
+
),…,由此猜测第n个不等式为
•(1+
+…+
)≥
•(
+…+
)
•(1+
+…+
)≥
•(
+…+
).
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| 1 |
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| 1 |
| 2 |
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| 4 |
| 1 |
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| 3 |
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| 5 |
| 1 |
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| 2 |
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| n+1 |
| 1 |
| 3 |
| 1 |
| 2n-1 |
| 1 |
| n |
| 1 |
| 2 |
| 1 |
| 2n |
| 1 |
| n+1 |
| 1 |
| 3 |
| 1 |
| 2n-1 |
| 1 |
| n |
| 1 |
| 2 |
| 1 |
| 2n |
化简:(1+2-
)(1+2-
)(1+2-
)(1+2-
)(1+2-
),结果是( )
| 1 |
| 32 |
| 1 |
| 16 |
| 1 |
| 8 |
| 1 |
| 4 |
| 1 |
| 2 |
A、
| ||||
B、(1+2-
| ||||
C、1-2-
| ||||
D、
|