摘要:18.知等差数列{an}的前n项和为Sn.且a3=5.S15=225. (Ⅰ)求数列{an}的通项an, (Ⅱ)设bn=+2n.求数列{bn}的前n项和Tn.
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(本小题满分12分)已知数列{an}的前n项和为Sn,且满足
an+2Sn·Sn-1=0(n≥2),a1=
.
(1)求证:{
}是等差数列;
(2)求an表达式;
(3)若bn=2(1-n)an(n≥2),求证:b22+b32+…+bn2<1.
(本小题满分12分)已知数列{an}的前n项和为Sn,且满足
an+2Sn·Sn-1=0(n≥2),a1=
.
(1)求证:{
}是等差数列;
(2)求an表达式;
(3)若bn=2(1-n)an(n≥2),求证:b22+b32+…+bn2<1.
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(本小题满分12分)已知数列{an}的前n项和为Sn,且满足
an+2Sn·Sn-1=0(n≥2),a1=
.
(1)求证:{
}是等差数列;
(2)求an表达式;
(3)若bn=2(1-n)an(n≥2),求证:b22+b32+…+bn2<1.
查看习题详情和答案>>