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在数列{an}中,a1=1,an+1=2an+2n.
(1)设,证明:数列{bn}是等差数列;
(2)求数列{an}的前n项和Sn.
(Ⅰ)设bn=.证明:数列{bn}是等差数列;
(Ⅱ)求数列{an}的前n项和Sn.