摘要:9.如图.P是⊙O外一点.割线PA.PB分别与⊙O相交于A.C.B.D四点.PT切⊙O于T.点E.F分别在PB.PA上.且PE = PT.∠PFE =∠ABP.(1)求证:PD·PF = PC·PE,(2)若PD = 4.PC = 5.AF = .求PT的长,
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①
AB=CD
;②
PB=PD
;③
∠B=∠D
.| AmB |
| A、x° | ||
B、(90-
| ||
| C、(90-x)° | ||
| D、(180-x)° |