摘要:4.计算:-9+(-13)-2003.3-8-(-7)-(+)-.
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计算:
(1)ym•ym+1
(2)(-2xy3z2)4
(3)(-3×103)2
(4)5x(2x2-3x+4)
(5)(2a-b)2(4a2+b2)2(2a+b)2
(6)[(x+1)(x+2)-2]÷x
(7)(-2003)0×2÷
×[(-
)2÷23].
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(1)ym•ym+1
(2)(-2xy3z2)4
(3)(-3×103)2
(4)5x(2x2-3x+4)
(5)(2a-b)2(4a2+b2)2(2a+b)2
(6)[(x+1)(x+2)-2]÷x
(7)(-2003)0×2÷
| 1 |
| 2 |
| 1 |
| 3 |
计算:
(1)-32-(-2)2; (2)-14-
×[2-(-3)2];
(3)(-10)2+[(-4)2-(3+32)×2]; (4)(-1)4-(1-0.5)×
×[2-(-2)2];
(5)-0.52+
-|-22-4|-(-1
)3×
; (6)(-2)3-3×[(-4)2+2]-(-3)2÷(-2);
(7)(-2)2003+(-2)2002; (8)(-0.25)2009×42008. 查看习题详情和答案>>
(1)-32-(-2)2; (2)-14-
| 1 |
| 6 |
(3)(-10)2+[(-4)2-(3+32)×2]; (4)(-1)4-(1-0.5)×
| 1 |
| 3 |
(5)-0.52+
| 1 |
| 4 |
| 1 |
| 2 |
| 4 |
| 9 |
(7)(-2)2003+(-2)2002; (8)(-0.25)2009×42008. 查看习题详情和答案>>