摘要:如图.已知在△ABC中.∠ABC.∠ACB的平分线相交于点O. (1)若∠ABC=500.∠ACB=650.则∠BOC= , (2)若∠ABC+∠ACB=1300.则∠BOC= , (3)若∠A=900.则∠BOC= , (4)若∠BOC=1000.则∠A=
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如图,已知在△ABC中,∠ABC=∠ACB,∠ABC的角平分线交AC于点D.
(1)请在图5中用尺规作∠ACB的平分线(不写作法,保留作留痕迹);
(2)设∠ACB的平分线交AB于点E,证明BD=CE.