ÌâÄ¿ÄÚÈÝ

ÔÚˮƽµØÃæMNÉÏ·½¸ß¶ÈΪh=0.45m´¦ÓÐÒ»¸ö´Ö²Ú¾øÔµÆ½Ì¨PQ£¬ÈçͼËùʾ£¬Æ½Ì¨ÉÏ·½PRÓÒ²àÓÐˮƽÏòÓÒµÄÓнçÔÈÇ¿µç³¡£¬³¡Ç¿E=1.1¡Á104N/C¡£ÓÐÒ»ÖÊÁ¿m=1.0¡Á10-3kg¡¢´øµçÁ¿Îªq=-1.0¡Á10-6CµÄ»¬¿é·ÅÔÚÆ½Ì¨ÉÏ£¬¾àÀëÆ½Ì¨×ó¶ËPµãL=0.5m´¦£¬»¬¿éÓëÆ½Ì¨µÄ»¬¶¯Ä¦²ÁÒòÊýΪ¡£ÏÖ¸ø»¬¿éˮƽÏò×óµÄ³õËÙ¶Èv0=4m/s£¬ÎÊ£º
£¨1£©»¬¿é¾­¹ýPµãʱµÄËٶȶà´ó£¿
£¨2£©»¬¿éÂ䵨µã¾àNµã¶àÔ¶£¿
£¨10·Ö£©½â£º£¨1£©Óɶ¯Äܶ¨Àí£º £¨3·Ö£©µÃ£º £¨2·Ö£©£¨2£©ÓÉ £¨2·Ö£©µÃ £¨1·Ö£© £¨2·Ö£©
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø