ÌâÄ¿ÄÚÈÝ

17£®ÊúÖ±Æ½ÃæÄÚ´æÔÚÒ»Õý·½ÐÎÇøÓòABCD£¬±ß³¤ÎªL£¬AC Îª¶Ô½ÇÏߣ¬Ò»´øµçÁ£×ÓÖÊÁ¿Îªm£¬µçºÉÁ¿Îª+q£¬ÖØÁ¦²»¼Æ£¬ÒÔˮƽ³õËÙ¶ÈΪv0´ÓA µãÉäÈëÕý·½ÐÎÇøÓò£¬¿ÉÔÚACD ÇøÓòÄÚ¼ÓÊúÖ±·½ÏòµÄÔÈÇ¿µç³¡»ò´¹Ö±Æ½ÃæµÄÔÈÇ¿´Å³¡£¬Ê¹µÃ´øµçÁ£×ÓÄÜ´ÓC µãÉä³ö³¡ÇøÓò£¬ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®¿ÉÔÚACD ÇøÓò¼ÓÊúÖ±ÏòϵÄÔÈÇ¿µç³¡
B£®¿ÉÔÚACD ÇøÓò¼Ó´¹Ö±Æ½ÃæÏòÀïµÄÔÈÇ¿´Å³¡
C£®¼Óµç³¡ºó´ÓC µãÉä³öÓë¼Ó´Å³¡ºó´ÓC µãÉä³öËùÐèʱ¼äÖ®±ÈΪ1£º2 ¦Ð
D£®Ëù¼Óµç³¡µÄµç³¡Ç¿¶ÈºÍ´Å³¡µÄ´Å¸ÐӦǿ¶ÈÖ®±ÈΪ2v0£º1

·ÖÎö ¸ù¾ÝÁ£×ӵį«×ª·½ÏòÅжϵ糡Á¦·½ÏòºÍÂåÂ××ÈÁ¦·½Ïò£¬·ÖÎöµç³¡µÄ·½Ïò£®ÓÉ×óÊÖ¶¨ÔòÅжϴų¡µÄ·½Ïò£®Á£×ÓÔڵ糡ÖÐ×öÀàÆ½Å×Ô˶¯£¬ÔËÓ÷ֽⷨÑо¿Ê±¼äºÍµç³¡Ç¿¶È£®Á£×ÓÔڴų¡ÖÐ×öÔÈËÙÔ²ÖÜÔ˶¯£¬¸ù¾Ý°ë¾¶¹«Ê½ºÍÖÜÆÚ¹«Ê½Ñо¿Ê±¼äºÍ´Å¸ÐӦǿ¶È£®

½â´ð ½â£ºA¡¢´øµçÁ£×Ó´¹Ö±ÉäÈëÔÈÇ¿µç³¡ºóÄÜ´ÓCµãÉä³ö³¡ÇøÓò£¬ËµÃ÷Á£×ÓÊܵ½µÄµç³¡Á¦·½ÏòÊúÖ±ÏòÏ£¬Á£×Ó´øÕýµç£¬ËùÒÔ¿ÉÔÚACD ÇøÓò¼ÓÊúÖ±ÏòϵÄÔÈÇ¿µç³¡£®¹ÊAÕýÈ·£®
B¡¢´øµçÁ£×Ó´¹Ö±ÉäÈëÔÈÇ¿´Å³¡ºóÄÜ´ÓCµãÉä³ö³¡ÇøÓò£¬Á£×ÓÔÚAµãÊܵ½µÄÂåÂ××ÈÁ¦ÊúÖ±ÏòÏ£¬ÓÉ×óÊÖ¶¨ÔòÅжÏÖª£¬¿ÉÔÚACD ÇøÓò¼Ó´¹Ö±Æ½ÃæÏòÍâµÄÔÈÇ¿´Å³¡£®¹ÊB´íÎó£®
C¡¢¼Óµç³¡Ê±£¬Á£×Óˮƽ·½Ïò×öÔÈËÙÖ±ÏßÔ˶¯£¬Ô˶¯Ê±¼äΪ t1=$\frac{L}{{v}_{0}}$£®¼Ó´Å³¡ºó£¬Á£×Ó×öÔÈËÙÔ²ÖÜÔ˶¯£¬Ô˶¯Ê±¼äΪ t2=$\frac{\frac{¦Ð}{2}L}{{v}_{0}}$=$\frac{¦ÐL}{2{v}_{0}}$
¹Êt1£ºt2=2£º¦Ð£®¹ÊC´íÎó£®
D¡¢¼Óµç³¡Ê±£ºÊúÖ±·½ÏòÓÐ L=$\frac{1}{2}a{t}_{1}^{2}$=$\frac{qE}{2m}•\frac{{L}^{2}}{{v}_{0}^{2}}$£»
¼Ó´Å³¡Ê±£¬ÓУºL=$\frac{m{v}_{0}}{qB}$£¬ÁªÁ¢½âµÃ E£ºB=2v0£º1£®¹ÊDÕýÈ·£®
¹ÊÑ¡£ºAD

µãÆÀ ½â¾ö±¾ÌâʱҪץס´øµçÁ£×ÓÔڵ糡ÖÐÀàÆ½Å×Ô˶¯µÄÑо¿·½·¨ÊÇ£ºÔ˶¯µÄ·Ö½â·¨£¬¶ø´øµçÁ£×ÓÔڴų¡ÖÐÔ²ÖÜÔ˶¯µÄÑо¿·½·¨ÊÇ»­³ö¹ì¼££¬¸ù¾ÝÔ²ÖÜÔ˶¯µÄ¹æÂÉÑо¿£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
12£®Ä³ÊµÑéС×éÓÃͼ¼×ËùʾµÄʵÑé×°Öá°Ì½¾¿¼ÓËÙ¶ÈÓëÁ¦¡¢ÖÊÁ¿µÄ¹ØÏµ¡±£®Í¼¼×ÖÐAΪС³µ£¬BΪװÓÐíÀÂëµÄСÅÌ£¬CΪһ¶Ë´øÓж¨»¬Âֵij¤Ä¾°å£¬Ð¡³µÍ¨¹ýÖ½´øÓëµç´Å´òµã¼ÆÊ±Æ÷ÏàÁ¬£¬Ð¡³µµÄÖÊÁ¿Îªml£¬Ð¡Å̼°íÀÂëµÄ×ÜÖÊÁ¿Îªm2£®

£¨1£©ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇC
A£®ÊµÑéʱÏÈ·Å¿ªÐ¡³µ£¬ÔÙ½Óͨ´òµã¼ÆÊ±Æ÷µÄµçÔ´
B£®Ã¿´Î¸Ä±äС³µÖÊÁ¿Ê±£¬Ó¦ÖØÐÂÆ½ºâĦ²ÁÁ¦
C£®±¾ÊµÑéÖÐÓ¦Âú×ãm2ԶСÓÚmlµÄÌõ¼þ
D£®ÔÚÓÃͼÏó̽¾¿Ð¡³µ¼ÓËÙ¶ÈaÓëС³µÖÊÁ¿mlµÄ¹ØÏµÊ±£¬Ó¦×÷³öa-mlͼÏó
£¨2£©ÊµÑéµÃµ½ÈçͼÒÒËùʾµÄÒ»ÌõÖ½´ø£¬A¡¢B¡¢C¡¢D¡¢EΪ¼ÆÊýµã£¬ÏàÁÚÁ½¸ö¼ÆÊýµãµÄʱ¼ä¼ä¸ôΪT£¬B¡¢CÁ½µãµÄ¼ä¾àx2ºÍD¡¢EÁ½µãµÄ¼ä¾àx4¼ºÁ¿³ö£¬ÀûÓÃÕâÁ½¶Î¼ä¾à¼ÆËãС³µ¼ÓËٶȵıí´ïʽΪa=$\frac{{x}_{4}-{x}_{2}}{2{T}^{2}}$£®
£¨3£©Ä³Í¬Ñ§Æ½ºâºÃĦ²Á×èÁ¦ºó£¬ÔÚ±£³ÖС³µÖÊÁ¿²»±äµÄÇé¿öÏ£¬Í¨¹ý¸Ä±äíÀÂë¸öÊý£¬µÃµ½¶à×éÊý¾Ý£¬µ«¸ÃͬѧÎó½«íÀÂëµÄÖØÁ¦µ±×÷Éþ×Ó¶ÔС³µµÄÀ­Á¦£¬×÷³öÁËС³µ¼ÓËÙ¶ÈaÓëíÀÂëÖØÁ¦FµÄͼÏóÈçͼ±ûËùʾ£®¾Ý´ËͼÏó·ÖÎö¿ÉµÃ£¬Ð¡³µµÄÖÊÁ¿Îª0.61kg£¬Ð¡Å̵ÄÖÊÁ¿Îª0.0061kg£®£¨g=10m/s2£¬±£ÁôÁ½Î»ÓÐЧÊý×Ö£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø