2.已知t为常数,函数f(x)=x2+tln(x+1)有两个极值点a,b(a<b),则( )
| A. | f(b)>$\frac{1-2ln2}{4}$ | B. | f(b)<$\frac{1-2ln2}{4}$ | C. | f(b)>$\frac{3+2ln2}{8}$ | D. | f(b)<$\frac{4+3ln2}{8}$ |
1.已知函数f(x)=$\left\{\begin{array}{l}{2{x}^{3}-a{x}^{2}-1,x<0}\\{|x-3|+a,x≥0}\end{array}\right.$恰有两个零点,则a的取值范围是( )
| A. | (-3,0) | B. | (-∞,0) | C. | (-∞,-3) | D. | (0,+∞) |
18.若函数f(x)=x3-(4+log2a)x+2在(0,2]上有两个零点,则实数a的取值范围是( )
| A. | $(\frac{1}{4},\left.1]\right.$ | B. | ($\frac{1}{2}$,2] | C. | [1,4) | D. | [2,8) |
17.以正四面体各面中心为顶点的新四面体的棱长是原四面体棱长的( )
0 231380 231388 231394 231398 231404 231406 231410 231416 231418 231424 231430 231434 231436 231440 231446 231448 231454 231458 231460 231464 231466 231470 231472 231474 231475 231476 231478 231479 231480 231482 231484 231488 231490 231494 231496 231500 231506 231508 231514 231518 231520 231524 231530 231536 231538 231544 231548 231550 231556 231560 231566 231574 266669
| A. | $\frac{1}{2}$ | B. | $\frac{1}{3}$ | C. | $\frac{1}{4}$ | D. | $\frac{1}{6}$ |