题目内容

已知双曲线W的左、右焦点分别为,点,右顶点是M,且
(Ⅰ)求双曲线的方程;
(Ⅱ)过点的直线l交双曲线W的右支于AB两个不同的点(BAQ之间),若点在以线段AB为直径的圆的外部,试求△AQH与△BQH面积之比λ的取值范围.
(1);(2).
(1)利用双曲线的基本量的运算和向量的数量积可得。(2)设出直线l的方程,要注意斜率存在且不为0,直线方程与双曲线方程联立利用判别式和韦达定理,点在以线段AB为直径的圆的外部,就是,得可得,再转化为横坐标运算,整理得,由求出
解:(Ⅰ)由已知
,则,∴,∴
解得,∴双曲线的方程为.·································· 4分
(Ⅱ)直线l的斜率存在且不为0,设直线l:,设
,则
解得.    ①································································· 6分
∵点在以线段AB为直径的圆的外部,则

,解得. ②
由①、②得实数k的范围是,······················································· 8分
由已知,∵BAQ之间,则,且
,则,∴
,··················································· 10分
,∴,解得,又,∴
λ的取值范围是.···································································· 13分
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