题目内容
计算下列各题
(1)
;
(2)
+
.
(1)-4
i(2)0
解析:
(1)
=![]()
=
=
i(1+i)4=
i[(1+i)2]2
=
i(2i)2=-4
i.
(2)
+
=
+![]()
=i+
=i+i1 003
=i+i4×250+3=i+i3=i-i=0.
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题目内容
计算下列各题
(1)
;
(2)
+
.
(1)-4
i(2)0
(1)
=![]()
=
=
i(1+i)4=
i[(1+i)2]2
=
i(2i)2=-4
i.
(2)
+
=
+![]()
=i+
=i+i1 003
=i+i4×250+3=i+i3=i-i=0.