题目内容
计算下列各题
(1)52log53+log432-log3(log28);
(2)(0.027)-
-(
)-2+(2
)
-(
-1)0.
(1)52log53+log432-log3(log28);
(2)(0.027)-
| 1 |
| 3 |
| 1 |
| 7 |
| 7 |
| 9 |
| 1 |
| 2 |
| 2 |
分析:(1)直接利用对数的运算性质求解表达式的值.
(2)利用指数的运算性质求解表达式的值即可.
(2)利用指数的运算性质求解表达式的值即可.
解答:解:(1)52log53+log432-log3(log28)
=5log532+log2225-log3(log223)
=9+
-1=
(2)(0.027)-
-(
)-2+(2
)
-(
-1)0
=[(0.3) 3]-
-(7)2+(
)
-1
=
-49+
-1
=-45.
=5log532+log2225-log3(log223)
=9+
| 5 |
| 2 |
| 21 |
| 2 |
(2)(0.027)-
| 1 |
| 3 |
| 1 |
| 7 |
| 7 |
| 9 |
| 1 |
| 2 |
| 2 |
=[(0.3) 3]-
| 1 |
| 3 |
| 25 |
| 9 |
| 1 |
| 2 |
=
| 10 |
| 3 |
| 5 |
| 3 |
=-45.
点评:本题考查指数与对数的运算性质的应用,考查计算能力.
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