题目内容
计算:
(1)2log510+log50.25+ln
+2log23
(2)(2a
b
)(-6a
b
)÷(-3a
b
)(a>0,b>0)
(1)2log510+log50.25+ln
| e |
(2)(2a
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 6 |
| 5 |
| 6 |
分析:(1)利用对数运算法则进行计算;
(2)利用有理数指数幂的运算法则进行计算;
(2)利用有理数指数幂的运算法则进行计算;
解答:解:(1)原式=log5102+log50.25+lne
+2log23
=log5102×0.25+
+3
=log525+
+3=2+
+3=
.
(2)原式=
a
+
-
b
+
-
=4a.
| 1 |
| 2 |
=log5102×0.25+
| 1 |
| 2 |
=log525+
| 1 |
| 2 |
| 1 |
| 2 |
| 11 |
| 2 |
(2)原式=
| 2×(-6) |
| -3 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 2 |
| 1 |
| 3 |
| 5 |
| 6 |
点评:本题考查对数运算法则及有理数指数幂的运算法则,熟练掌握相关运算法则是解决该类题目的基础.
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