题目内容
(1)已知sinθ+cosθ=
,求sin2θ的值.
(2)化简cos40°(1+
tan10°).
| ||
| 3 |
(2)化简cos40°(1+
| 3 |
(1)∵sinθ+cosθ=
,
∴(sinθ+cosθ)2=sin2θ+cos2θ+2sinθ•cosθ
=1+sin2θ
=
,
∴sin2θ=
.
(2)cos40°(1+
tan10°)
=cos40°(1+
•
)
=
(cos10°+
sin10°)
=
•2sin40°
=
=1.
| ||
| 3 |
∴(sinθ+cosθ)2=sin2θ+cos2θ+2sinθ•cosθ
=1+sin2θ
=
| 4 |
| 3 |
∴sin2θ=
| 1 |
| 3 |
(2)cos40°(1+
| 3 |
=cos40°(1+
| 3 |
| sin10° |
| cos10° |
=
| cos40° |
| cos10° |
| 3 |
=
| cos40° |
| cos10° |
=
| sin80° |
| cos10° |
=1.
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