题目内容
设P为等边△ABC所在平面内的一点,满足
=
+2
,若AB=1,则
•
的值为( )
| CP |
| CB |
| CA |
| PA |
| PB |
| A.4 | B.3 | C.2 | D.1 |
因为
•
=(
+
)•(
+
)
=
•
+
•(
+
)+
•
=(
+2
)•(
+2
)-(
+2
)•(
+
)+
•
=2
2+2
•
=2×12+2×1×1×
=3.
故选 B.
| PA |
| PB |
| PC |
| CA |
| PC |
| CB |
=
| PC |
| PC |
| PC |
| CA |
| CB |
| CA |
| CB |
=(
| CB |
| CA |
| CB |
| CA |
| CB |
| CA |
| CA |
| CB |
| CA |
| CB |
=2
| CA |
| CA |
| CB |
=2×12+2×1×1×
| 1 |
| 2 |
=3.
故选 B.
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