Question

9．计算：$\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1=9．

Answer 1

分析 $\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1=$\frac{1-9×\frac{1}{6}×4}{-\frac{1}{9}}$×$\frac{1}{5}$=$\frac{1-6}{-\frac{1}{9}}$×$\frac{1}{5}$=9，即可求得$\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1．

解答 解：$\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1=$\frac{1-9×\frac{1}{6}×4}{-\frac{1}{9}}$×$\frac{1}{5}$=$\frac{1-6}{-\frac{1}{9}}$×$\frac{1}{5}$=（-5）×（-9）×$\frac{1}{5}$=9，
∴$\frac{1{2}^{0}-{3}^{2}×{6}^{-1}×{2}^{2}}{-{3}^{-2}}$×5^-1=9，
故答案为：9．

点评 本题考查有理数指数幂的化简求值，考查有理数幂的运算，考查计算能力，属于基础题．