题目内容
已知△ABC,点H,O为△ABC所在平面内的点,且
•
=
•
,
•
=
•
,
+
+
=
,则点O为△ABC的( )
| AH |
| AB |
| AH |
| AC |
| BH |
| BA |
| BH |
| BC |
| OA |
| OB |
| OC |
| OH |
| A.内心 | B.外心 | C.重心 | D.垂心 |
∵
•
=
•
,∴(
-
)•
=0
即
•
=0
又
+
+
=
,∴
+
=
-
,即
=
+
,
∴
•(
+
)=0,即(
-
)•(
+
)=0,
∴|
|2=|
|2,∴OB=OB
同理OA=OC,
∴O是△ABC的垂心.
故选B.
| AH |
| AB |
| AH |
| AC |
| AB |
| AC |
| AH |
即
| CB |
| AH |
又
| OA |
| OB |
| OC |
| OH |
| OB |
| OC |
| OH |
| OA |
| AH |
| OB |
| OC |
∴
| CB |
| OB |
| OC |
| OB |
| OC |
| OB |
| OC |
∴|
| OB |
| OC |
同理OA=OC,
∴O是△ABC的垂心.
故选B.
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