题目内容
如图,O,A,B是平面上的三点,向量
=
,
=
设P为线段AB的垂直平分线CP上任意一点,向量
=
,若|
|=4,|
|=2,则
•(
-
)=( )

| OA |
| a |
| OB |
| b |
| OP |
| P |
| . |
| a |
| . |
| b |
| p |
| a |
| b |
| A.1 | B.3 | C.5 | D.6 |
由 |
|=|
|,知|
-
|=|
-
|,
∴|
-
|2=|
-
|2,
2-2
•
+
2=
2-2
•
+
2,
得 2
•
-2
•
=
2-
2=16-4=12,
∴
•(
-
)=6
故选D.
| BP |
| AP |
| p |
| b |
| p |
| a |
∴|
| p |
| b |
| p |
| a |
| p |
| p |
| b |
| b |
| p |
| p |
| a |
| a |
得 2
| p |
| a |
| p |
| b |
| a |
| b |
∴
| p |
| a |
| b |
故选D.
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