题目内容
【题目】已知△ABC的面积为8,cosA=
,D为BC上一点,
=
+
,过点D做AB,AC的垂线,垂足分别为E,F,则
= .
【答案】﹣ ![]()
【解析】解:如图所示,
![]()
△ABC中,cosA=
,∴sinA=
=
;
∴S△ABC=
|
||
|sinA=
|
||
|
=8,
即|
||
|=20;
设
=λ
,λ∈(0,1),
则
=
+
=
+λ(
﹣
)=(1﹣λ)
+λ
,
又
=
+
,∴λ=
;
∴
=
=
=
=3,
∴S△ABD=
|
||
|=
×8=6,
∴|
||
|=12;
又S△ACD=
|
||
|=2,
∴|
||
|=4;
∴|
||
||
||
|=48,
∴|
||
|=
=
,
∴
=|
||
|cos(180°﹣A)=
×(﹣
)=﹣
.
所以答案是:﹣
.
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