题目内容
已知cos(75°+α)=
答案:-![]()
解析:∵cos(105°-α)=cos[180°-(75°+α)]=-cos(75°+α)=-
, sin(α-105°)=-sin(105°-α)=-sin[180°-(75°+α)]=-sin(75°+α),?∵cos(75°+α)=
>0,且α为第三象限角,故75°+α为第四象限角,故sin(75°+α)=-
=-
.故原式=-
-
=-
.
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题目内容
已知cos(75°+α)=
答案:-![]()
解析:∵cos(105°-α)=cos[180°-(75°+α)]=-cos(75°+α)=-
, sin(α-105°)=-sin(105°-α)=-sin[180°-(75°+α)]=-sin(75°+α),?∵cos(75°+α)=
>0,且α为第三象限角,故75°+α为第四象限角,故sin(75°+α)=-
=-
.故原式=-
-
=-
.