题目内容

设D为△ABC的边AB上一点,P为△ABC内一点,且满足
AD
=
2
3
AB
AP
=
AD
+
1
4
BC
,则
SAPD
SABC
=(  )
A.
2
9
B.
1
6
C.
7
54
D.
4
27
由题意,
AP
=
AD
+
DP
AP
=
AD
+
1
4
BC

DP
=
1
4
BC

三角形ADP的高
三角形ABC
=
AD
AB
=
2
3

S△APD
S△ABC
=
2
3
×
1
4
=
1
6

故选B.
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