题目内容
已知△OAB中,点C是点B关于点A的对称点,点D是线段OB的一个靠近B的三等分点,设
=
,
=
.
(1)用向量
与
表示向量
,
;
(2)若
=
,求证:C、D、E三点共线.

| AB |
| a |
| AO |
| b |
(1)用向量
| a |
| b |
| OC |
| CD |
(2)若
| OE |
| 4 |
| 5 |
| OA |
(1)∵
=
,
=
∴
=
+
=-
-
=
+
=
+
=
+
(
+
)=2
+
(-
+
)=
+
(2)∵
=
-
=
(-
)+
+
=
+
=
∴
与
又∵
与
有公共点C,
∴C、D、E三点共线
| AB |
| a |
| AO |
| b |
∴
| OC |
| OA |
| AC |
| a |
| b |
| CD |
| CB |
| BD |
| CB |
| 1 |
| 3 |
| BO |
| CB |
| 1 |
| 3 |
| BA |
| AO |
| a |
| 1 |
| 3 |
| a |
| b |
| 5 |
| 3 |
| a |
| 1 |
| 3 |
| b |
(2)∵
| CE |
| OE |
| OC |
| 4 |
| 5 |
| b |
| a |
| b |
| a |
| 1 |
| 5 |
| b |
| 3 |
| 5 |
| CD |
∴
| CE |
| CD |
又∵
| CE |
| CD |
∴C、D、E三点共线
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