题目内容
计算:
(1)(2
)
-(-9.6)0-(3
) -
+(1.5)-2;
(2)lg
-lg
+lg12.5-log89•log34+2log0.53.
(1)(2
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 8 |
| 2 |
| 3 |
(2)lg
| 1 |
| 2 |
| 5 |
| 8 |
分析:(1)利用指数式的运算法则,把(2
)
-(-9.6)0-(3
) -
+(1.5)-2等价转化为
-1-
+
,由此能求出结果.
(2)利用对数式的运算法则,把lg
-lg
+lg12.5-log89•log34+2log0.53等价转化为lg(
×
×12.5)-
•
+2log
3,由此能求出结果.
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 8 |
| 2 |
| 3 |
| 3 |
| 2 |
| 4 |
| 9 |
| 4 |
| 9 |
(2)利用对数式的运算法则,把lg
| 1 |
| 2 |
| 5 |
| 8 |
| 1 |
| 2 |
| 8 |
| 5 |
| lg9 |
| lg8 |
| lg4 |
| lg3 |
| 1 |
| 2 |
解答:解:(1)(2
)
-(-9.6)0-(3
) -
+(1.5)-2
=
-1-
+
=
.
(2)lg
-lg
+lg12.5-log89•log34+2log0.53
=lg(
×
×12.5)-
•
+2log
3
=1-
+
=0.
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 8 |
| 2 |
| 3 |
=
| 3 |
| 2 |
| 4 |
| 9 |
| 4 |
| 9 |
=
| 1 |
| 2 |
(2)lg
| 1 |
| 2 |
| 5 |
| 8 |
=lg(
| 1 |
| 2 |
| 8 |
| 5 |
| lg9 |
| lg8 |
| lg4 |
| lg3 |
| 1 |
| 2 |
=1-
| 4 |
| 3 |
| 1 |
| 3 |
=0.
点评:本题考查对数和指数的运算法则和运算性质,是基础题.解题时要认真审题,仔细解答.
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