题目内容

(本小题满分13分)设等差数列满足.

(1)求的通项公式;

(2)求数列的前n项和Sn及使得Sn最大的序号n的值.

 

【答案】

解:(1) 由

   解得  

··························································································· 6分

(2) 由 (1) 知,

 

∴当n = 5时,Sn取得最大·········································································· 13分

【解析】略

 

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