题目内容
已知4a+5b=20(a>0,b>0),则
+
的最小值为( )
| 5 |
| a |
| 1 |
| b |
A.
| B.
| C.1 | D.4 |
∵4a+5b=20(a>0,b>0),
∴
+
=
(4a+5b)(
+
)=
(25+
+
)≥
(25+2
)=
,当且仅当a=
,b=
时取等号.
故选B.
∴
| 5 |
| a |
| 1 |
| b |
| 1 |
| 20 |
| 5 |
| a |
| 1 |
| b |
| 1 |
| 20 |
| 25b |
| a |
| 4a |
| b |
| 1 |
| 20 |
|
| 9 |
| 4 |
| 10 |
| 3 |
| 4 |
| 3 |
故选B.
练习册系列答案
相关题目