题目内容
已知tanα=
,α∈(0,
),则cos(
+α)=______.
| 1 |
| 2 |
| π |
| 2 |
| π |
| 4 |
∵tanα=
,α∈(0,
),
∴cosα=
=
,
∴sinα=
=
,
则cos(
+α)=cos
cosα-sin
sinα
=
×
-
×
=
.
故答案为:
| 1 |
| 2 |
| π |
| 2 |
∴cosα=
| 1 | ||
|
2
| ||
| 5 |
∴sinα=
| 1-cos2α |
| ||
| 5 |
则cos(
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
=
| ||
| 2 |
2
| ||
| 5 |
| ||
| 2 |
| ||
| 5 |
=
| ||
| 10 |
故答案为:
| ||
| 10 |
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