题目内容
已知sin(α-
)=
,α∈(0,
),则sinα=______.
| π |
| 4 |
| 3 |
| 5 |
| π |
| 2 |
由α∈(0,
),得α-
∈(-
,
),故由已知sin(α-
)=
,可得cos(α-
)=
.
则sinα=sin[(α-
)+
]=sin(α-
)cos
+cos(α-
)sin
=
×
+
×
=
.
故答案为
.
| π |
| 2 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| 3 |
| 5 |
| π |
| 4 |
| 4 |
| 5 |
则sinα=sin[(α-
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| 3 |
| 5 |
| ||
| 2 |
| 4 |
| 5 |
| ||
| 2 |
7
| ||
| 10 |
故答案为
7
| ||
| 10 |
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