题目内容
已知z=
,则
=______.
| 1 |
| 1+i |
| . |
| z |
∵z=
=
=
-
i,
∴z的共轭复数是
+
i,
故答案为:
+
i
| 1 |
| 1+i |
| 1-i |
| (1+i)(1-i) |
| 1 |
| 2 |
| 1 |
| 2 |
∴z的共轭复数是
| 1 |
| 2 |
| 1 |
| 2 |
故答案为:
| 1 |
| 2 |
| 1 |
| 2 |
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题目内容
| 1 |
| 1+i |
| . |
| z |
| 1 |
| 1+i |
| 1-i |
| (1+i)(1-i) |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |