题目内容
(1)已知cos((2)已知cos(75°+α)=
,其中α为第三象限角,求cos(150°-α)+sin(α-105°)的值.
分析:(1)(
+α)+(
-α)=π.(2)(75°+α)+(105°-α)=180°,这样就可以用诱导公式求解.
解:(1)cos(
-α)=-cos[π-(
-α)]
=-cos(
+α)=
.
(2)cos(105°-α)=cos[180°-(75°+α)]
=-cos(75°+α)=
.
sin(α-105°)=-sin(105°-α)=-sin[180°-(75°+α)]=-sin(75°+α).
∵cos(75°+α)=
>0,又α为第三象限角,可知75°+α为第四象限角.
则有sin(75°+α)=
;
则cos(105°-α)+sin(α-105°)
=![]()
=
.
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