题目内容

(1)已知cos(+α)=,求cos(-α)的值.

(2)已知cos(75°+α)=,其中α为第三象限角,求cos(150°-α)+sin(α-105°)的值.

分析:(1)(+α)+(-α)=π.(2)(75°+α)+(105°-α)=180°,这样就可以用诱导公式求解.

解:(1)cos(-α)=-cos[π-(-α)]

=-cos(+α)=.

(2)cos(105°-α)=cos[180°-(75°+α)]

=-cos(75°+α)=.

sin(α-105°)=-sin(105°-α)=-sin[180°-(75°+α)]=-sin(75°+α).

∵cos(75°+α)=>0,又α为第三象限角,可知75°+α为第四象限角.

则有sin(75°+α)=;

则cos(105°-α)+sin(α-105°)

=

=.

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