题目内容
已知cos(75°+α)=
,其中α为第三象限角,求cos(105°-α)+sin(α-105°)的值.
答案:
解析:
解析:
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解:cos(105°-α)=cos[180°-(75°+α)]=-cos(75°+α)= sin(α-105°)=-sin(105°-α)=-sin[180°-(75°+α)]=-sin(75°+α). ∵cos(75°+α)= 则有sin(75°+α)= 故cos(105°-α)+sin(α-105°)= |
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